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riadik2000 [5.3K]
3 years ago
6

Simplify the following expression (x^5)^2=x^n A. 7 B. 10 C. -2 D. 9

Mathematics
1 answer:
Evgen [1.6K]3 years ago
4 0

Answer:

This is the farthest I could go in solving the equation. Is there anymore information about the problem? Unless you are looking for n which it would seem n would equal 10.

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let's call G the intersection point of EF & BC.

according to the thales' theorem:

\frac{eg}{ef}  =  \frac{bc}{ad}

and EF= EG+GF=EG+3

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When solving negative one over five -1/5 (x − 25) = 7, what is the correct sequence of operations
aleksandr82 [10.1K]

The solution would be like this for this specific problem:

 

\left( { - 5} \right)
\cdot \left( { - \frac{1}{5}} \right) \cdot \left( {x - 25} \right) = 7 \cdot
\left( { - 5} \right)

 

 

\left( { - 5} \right)
\cdot \left( { - \frac{1}{5}} \right) = 1

 

The correct sequence of operations when solving negative one over five (x − 25) = 7 would be multiply each side by −5, and adding 25 to each side.

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