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AlladinOne [14]
3 years ago
15

davis bought some candy for $35. this was seven dollars less than four times what he bought at the movie store. how much did he

spend at the movie store
Mathematics
1 answer:
bezimeni [28]3 years ago
4 0

The amount spent at the movie store is $ 10.5

<h3><u>Solution:</u></h3>

Given that Davis bought some candy for $ 35

This was seven dollars less than four times what he bought at the movie store

Which means that $ 35 is equal to seven dollars less than four times what he bought at the movie store

Let "m" be the amount spent at the movie store

$ 35 = seven dollars less than four times what he bought at the movie store

35 = 4m - 7

35 + 7 = 4m

42 = 4m

<h3>m = 10.5</h3>

Thus the amount spent at the movie store is $ 10.5

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14 kilometers x 4 kilo/minute = 56 minutes

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3 years ago
A bag of marbles contains 13 red marbles, 9 blue marbles, and 12 green marbles. If one marble is chosen at random, which is the
Pachacha [2.7K]

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B. 11/17

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12 - 34 = 22

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Hope this helps!

4 0
3 years ago
Ill give brainliest please help with this algebra!!
creativ13 [48]

Answer:

Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.

This will <em>always</em> give you a value of 1, as long as the denominator does not end up with a zero value.

Take for instance the third question:

\frac{p^4}{p^4}\\= p^4 \times p^{-4}\\= p^{(4 - 4)}\\= p^0\\= 1

This stands true with all three questions.

HOWEVER

I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple.  Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.

It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.

If that's case, we can solve it the same way we solved question 20.  If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:

\frac{(4x + 2y)\times5}{(4x + 2y)^5}\\= 5(4x + 2y) \times (4x + 2y)^{-5}\\= 5(4x + 2y)^1 \times (4x + 2y)^{-5}\\= 5(4x + 2y)^{1 - 5}\\= 5(4x + 2y)^{-4}\\= \frac{5}{(4x + 2y)^{4}}

Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent.  If it is instead a coefficient though, then this would be the answer to it.

8 0
3 years ago
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13 \times x = 1764

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