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Andrei [34K]
3 years ago
11

What is the equation of this line? y=3/2x −2 y=−2x+3/2 y=−2x+2/3 y=2/3x −2

Mathematics
1 answer:
podryga [215]3 years ago
7 0
The answer is the last one, y = 2/3 -2
Use the rise over run strategy on linear functions such as this one
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The profits in a business are to be shared by the three partners in the ratio of 3 to 2 to 5, in that order. The profit for the
jeka94

Answer:

The first partner will receive $52950, the second partner will receive $35300, the third partner will receive $88250.

Step-by-step explanation:

The profits in the business are to be shared by the three partners in the ratio of 3 to 2 to 5, in that order.

That is:

3 : 2 : 5

The profit for the year was $176,500.

To find the number of dollars that each partner, we have to first find the total ratio and then divide each of the ratios by the total ratio and multiply by the profit.

The total ratio is:

3 + 2 + 5 = 10

The first partner will receive 3/10 of the profits:

\frac{3}{10} * 176500 = $52950

The second partner will receive 2/10 of the profits:

\frac{2}{10} * 176500 = $35300

The third partner will receive 5/10 of the profits:

\frac{5}{10} * 176500 = $88250

The first partner will receive $52950, the second partner will receive $35300, the third partner will receive $88250.

7 0
3 years ago
(07.03 MC)
Umnica [9.8K]

The probability of pulling a blue marble and the coin landing tails up is 360/2500

<h3>How to determine the probability?</h3>

The tables of values are given as:

Color     Times

Blue        18

Green     20

Yellow    12

Heads    Tails

20          30

The probability of obtaining a blue marble is:

P(Blue) = 18/50

The probability of landing tails up is:

P(Tail) = 20/50

The required probability is:

P = P(Blue) * P(Tail)

This gives

P = 18/50 * 20/50

Evaluate the product

P = 360/2500

Hence, the probability of pulling a blue marble and the coin landing tails up is 360/2500

Read more about probability at:

brainly.com/question/25870256

#SPJ1

8 0
2 years ago
timothyis re-arranging his marbles collection. he has 5 identical blue marbles, five green and 3 black. he can fit excactly 5 ma
Lerok [7]
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are  blue-green-black.

Now the rest of the collection consists of

                    4 blue
                    4 green
                    2 black

and there's space for 2 more marbles in the case.

So the question really asks:  "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"

-- Well, there are 10 marbles all together. 
So the first one chosen can be any one of the 10,
       and for each of those,
the second one can be any one of the remaining 9 .

Total number of ways to pick 2 out of the 10  =  (10 x 9)  =  90 ways.

-- BUT ... there are not nearly that many different combinations
to wind up with in the case.    

The first of the two picks can be any one of the 3 colors,
             and for each of those,
the second pick can also be any one of the 3 colors. 

So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
6 0
3 years ago
Find the perimeter of the polygon
malfutka [58]
The answer is 24. 
8 + 8 + 4 + 4 = 24
7 0
3 years ago
Read 2 more answers
A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240m2?
GREYUIT [131]

Answer:

The values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

Step-by-step explanation:

Given

The base of triangle b = 2x+1

The height of triangle h = 6x-3

The Area of the triangle A = 240 m²

The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)

480=\left(2x+1\right)\left(6x-3\right)

480=12x^2-3

Subtract 480 from both sides

12x^2-3-480=480-480

12x^2-483=0

3\left(4x^2-161\right)=0

3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0

solving

2x+\sqrt{161}=0

2x=-\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{-\sqrt{161}}{2}

x=-\frac{\sqrt{161}}{2}

also solving

2x-\sqrt{161}=0

2x=\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{\sqrt{161}}{2}

x=\frac{\sqrt{161}}{2}

Therefore, the values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

3 0
3 years ago
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