3 years ago

Solve the system of equations 3r – 4s = 0 and 2r 5s = 23.

Mathematics

1 answer:

UkoKoshka [18]3 years ago

3 0

this is when its solved: r=4, s=3}

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irga5000 [103]

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So, circle the 0 after the equals sign because the equation does not equal 0.

Anything raised by the power of 0 is 1.

This is known as the zero exponent rule :)

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A restaurant owner mixed the juices of 7 lemons with every 3 oranges to make a special drink

alexandr1967 [171]

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2 years ago

Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly low, μ- 2σ , and the maximum val

allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

$n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\$

Using the binomial distribution: $\mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186$

In this the maximum value which is significantly low, $\mu-2\sigma$ , and the minimum value which is significantly high, $\mu+2\sigma$ , that is equal to: