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Diano4ka-milaya [45]

3 years ago

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Mathematics

1 answer:

nadya68 [22]3 years ago

8 0

Hi lol I don’t understand you’re question I need more context

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How could you solve this equation -4= -17+x

never [62]

i belive you add 17 on both sidees to find x

4 0

4 years ago

Read 2 more answers

Please help me! 10 points

Lerok [7]

the answer is d or the last one

5 0

3 years ago

3. Six less than twice a number is 17. Which equation could be used to determine the

Usimov [2.4K]

Answer & Step-by-step explanation:

n represents our number. So, twice a number would be 2n because twice means multiply by two.

When the problem says 6 less, then it means 6 less than 2n. So, it would look like 2n-6.

FInally, the problem says that all of this equals 17 so 17 would be the result.

So, you answer is 2n-6 = 17. This is answer choice B.

6 0

3 years ago

Is this a function? (4,12) (4,15) (5,18) (5,21) (6,24)

cluponka [151]

Answer:

No this is not a function.

Step-by-step explanation:

This is not a function because some of the x-values repeat, which is not how a function works. For this to be a function, each x-value would have to be different. In this case, the 4 and 5 repeat in the x-values.

If this answer is correct, please make me Brainliest!

8 0

3 years ago

Give an example of each of the following or explain why you think such a set could not exist.

Oksanka [162]

Answer:

a.No

b.No

c.No

Step-by-step explanation:

a.No,Such set does not exist .A set of natural numbers is N

Every point of this set is an isolated point but no accumulation point

Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

$(a-\epsilon,e+\epsilon)\cap S-{a}\neq\phi$

Isolated point : it is defined as that point a of set S which neighborhood does not contain any other point of set except itself

$(a-\epsilon0,a+\epsilon)\cap S-{a}=\phi$

Interior point of set :Let $a\in S$ .Then a is called interior point of set when its neighborhood is a subset of set S.

$a\in(a-\epsilon,e+\epsilon)\subset S$

When a set is uncountable then interior point exist it is necessary for interior points existance .

Boundary points :Let $a\in S$ .If every non empty neighborhood of a intersect S and complement of S.

Every member of a set is a boundary point

b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers

c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of boundary point and isolated point

6 0

3 years ago