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3 years ago

What is the mean for the following set of population scores:

Mathematics

2 answers:

Fofino [41]3 years ago

7 0

Answer:

8.2944444444444

Step-by-step explanation:

Leona [35]3 years ago

4 0

the mean is 8

please give me a brainlest!

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In trapiziod ABCD with bases AB and DC , diagonals intersect at point O. Find the length of diagonal BD, if BO=6 cm and A/O=3/1

ElenaW [278]

Answer:

the length of the diagonal BD is 8 cm

Step-by-step explanation:

The computation of the length of diagonal BD is as follows

Here the trapezoid diagonals divides each other in an equivalent ratio

So, equation would be

AO ÷ OC = OB ÷ OD

Now put there values to the above equation

3 ÷ 1 = 6 ÷ OD

3OD = 6

Now divided it by 3 in both the sides

OD = 2

Now the BD would be

= BO + OD

= 6 + 2

= 8 cm

hence, the length of the diagonal BD is 8 cm

3 0

3 years ago

Determine the area and outer perimeter of the L O V E

lisabon 2012 [21]

Answer:

L is 75, O is 114, V is 76, E is 90

Step-by-step explanation:

I did it with Multiplication from the widths, and lengths

8 0

2 years ago

Micah is a busy college student. He carries a full load of classes and works a full time job to support himself financially whil

Fantom [35]

Answer:

32 school hrs in a week.

Step-by-step explanation:

The reduction percentage =

80 x 0.80 = 64 (hrs)

The distribution =

64/2 = 32hrs

8 0

3 years ago

A STUDENT'S NOTEBOOK CONTAINS 78 SHEETS OF PAPER. ONE-FOURTH OF THE

frutty [35]

Answer: I believe the Awnser is 18.75

Step-by-step explanation:all you have to do is divide 78 and 1/4

6 0

3 years ago

A patient is given a 100-milligram dosage of a drug that decays exponentially at a rate of 11% per hour. The doctor wants to kno

I am Lyosha [343]

Answer:

This is an example of exponential decay (somewhat similar to half-life).

If it decays at 11% per hour we can calculate its half-life by this formula:

half life = [ time • ln (2) ] ÷ ln (beginning amount ÷ ending amount)

where "ln" means natural log

half life =[ 1 hour * .69315] / ln (100 / 89)

half life =[.69315] / ln (1.1235955056)

half life =[.69315] / 0.11653381624

half life = 5.9481 hours

We need "lambda" "λ" (the decay constant) which equals

λ = ln(2) / half-life = .693147 / 5.9481 = 0.1165325062

Now we need a formula for the time required:

time = ln (Nt ÷ N0) ÷ -λ where No = beginning amount (100 milligrams) Nt = ending amount (15 milligrams)

time = ln (15 ÷ 100) ÷ -0.1165325062

time = ln (.15) / -0.1165325062

time = -1.8971199849 / -0.1165325062

time = 16.2797492885 hours

Source: https://www.1728.org/halflif2.htm

Step-by-step explanation:

4 0

3 years ago