All categories

3 years ago

What currents are responsible for powering the movement of tectonic plates ? A. Platonic B. Tectonic C. Convection D. Plutonium

Physics

2 answers:

allsm [11]3 years ago

4 0

Convection currents are responsible for powering the movement of tectonic plates.

Ivan3 years ago

3 0

The currents responsible for powering the movement of tectonic plates is convection currents which occur in the mantle. As the hotter, less dense liquid rises it displaces the cooler more dense liquid which moves the tectonic plates out of allignment

You might be interested in

A car is traveling down the highway at speed 5 m/s when the driver slams on the brakes and skids to a stop in a distance 80 m. A

Murljashka [212]

The car is very incredibly fast

8 0

4 years ago

What's the temperature 414 K in degrees Celsius?

olga nikolaevna [1]

Answer:

140.85 is the correct answer

6 0

2 years ago

Pressure and volume changes at a constant temperature can be calculated using

V125BC [204]

Answer:

Option A, Boyle's law

Explanation:

The complete question is

Pressure and volume changes at a constant temperature can be calculated using

a. Boyle's law. c. Kelvin's law.

b. Charles's law. d. Dalton's law.

Solution

In Boyle’s law, the gas is assumed to be ideal gas and at constant temperature. With these two conditions fixed, Boyle’s established that volume of gas varies inversely with the absolute pressure.

The basic mathematical representation of this phenomenon is as follows -

$P \alpha \frac{1}{V}$

$P = \frac{k}{V} \\PV = k$

Where P is the pressure of ideal gas, V is the volume and k is the constant of proportionality.

Hence, option A is correct

3 0

3 years ago

You buy a magnifying glass at the store. The lens in the magnifying glass is a double convex lens, a lens with two convex curved

Leokris [45]

Answer:

30 cm

Explanation:

f = Focal length = 25 cm

R = Radius of curvature (both sides are equal)

$\mu$ = Refractive index of lens = 1.6

The lens maker formula is given by

$\frac{1}{f}=(\mu-1)(\frac{1}{R_1}-\frac{1}{R_2})\\\Rightarrow \frac{1}{f}=(\mu-1)(\frac{1}{R}-\frac{1}{-R})$ minus sign because it is on the other side

$\\\Rightarrow \frac{1}{f}=(\mu-1)\frac{2}{R}\\\Rightarrow R=2(\mu-1)f\\\Rightarrow R=2(1.6-1)\times 25\\\Rightarrow R=30\ cm$

The radius of curvature of the glass surface is 30 cm

8 0

4 years ago

A 1.0 kg object is attached to a string 0.50 m. It is twirled in a horizontal circle above the ground at a speed of 5.0 m/s. A b

aivan3 [116]

<span>50 N The centripetal force upon an object is expressed as F = mv^2/r So let's substitute the known values and calculate F = mv^2/r F = 1.0 kg * (5.0 m/s)^2 / 0.5 m F = 1.0 kg * 25 m^2/s^2 / 0.5 m F = 25 kg*m^2/s^2 / 0.5 m F = 50 kg*m/s^2 F = 50 N So the answer is 50 N which matches one of the available choices.</span>

6 0

3 years ago