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3 years ago

What currents are responsible for powering the movement of tectonic plates ? A. Platonic B. Tectonic C. Convection D. Plutonium

Physics

2 answers:

allsm [11]3 years ago

4 0

Convection currents are responsible for powering the movement of tectonic plates.

Ivan3 years ago

3 0

The currents responsible for powering the movement of tectonic plates is convection currents which occur in the mantle. As the hotter, less dense liquid rises it displaces the cooler more dense liquid which moves the tectonic plates out of allignment

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A Submerged Ball Part A A ball of mass mb and volume V is lowered on a string into a fluid of density Pi (Figure 1) Assume that

frozen [14]

Answer:

T = mg - $\rho_f$ ×V×g

Explanation:

Here we have the mass of the ball is given as $m_b$

The density of the fluid = $\rho_f$

The volume of the ball = V

Acceleration due to gravity = g

According to Archimedes's principle, the upthrust = Weight of fluid displaced

Tension in string = T = weight of ball - upthrust

T = mg - $\rho_f$ ×V×g

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3 years ago

When an athlete holds the barbell directly over his head, the force he exerts on the barbell is the same as the force exerted by

frutty [35]

Answer:

Explained

Explanation:

When the barbell is accelerated upward, the force exerted by the athlete is greater than the weight of the barbell. (The barbell, simultaneously, pushes with greater force against the athlete.) When acceleration is downward, the force supplied by the athlete is less than the force applied by the barbell on the athlete.

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3 years ago

Two blocks are connected by a light string that passes over two frictionless pulleys. The block of mass m2 is attached to a spri

irina1246 [14]

(BELOW YOU CAN FIND ATTACHED THE IMAGE OF THE SITUATION)

Answer:

$d=\frac{2g(m1-m2)}{k}$

Explanation:

For this we're going to use conservation of mechanical energy because there are nor dissipative forces as friction. So, the change on mechanical energy (E) should be zero, that means:

$E_{i}=E_{f}$

$K_{i}+U_{i}=K_{f}+U_{f}$ (1)

With $K_{i}$ the initial kinetic energy, $U_{i}$ the initial potential energy, $K_{f}$ the final kinetic energy and $U_{f}$ the final potential energy. Note that initialy the masses are at rest so $K_{i} = 0$ , when they are released the block 2 moves downward because m2>m1 and finally when the mass 2 reaches its maximum displacement the blocks will be instantly at rest so $K_{f} =0$ . So, equation (1) becomes:

$U_{i}=U_{f}$ (2)

At initial moment all the potential energy is gravitational because the spring is not stretched so $U_{i}=U_{gi}$ and at final moment we have potential gravitational energy and potential elastic energy so $U_{f}=U_{gf}+U_{ef}$ , using this on (2)

$U_{gi}=U_{gf}+U_{ef}$ (3)

Additional if we define the cero of potential gravitational energy as sketched on the figure below (See image attached), $U_{gi}=0$ and we have by (3) :

$0= U_{gf}+U_{ef}$ (4)

Now when the block 1 moves a distance d upward the block 2 moves downward a distance d too (to maintain a constant length of the rope) and the spring stretches a distance d, so (4) is:

$0=-m1gd+m2gd+\frac{kd^{2}}{2}$