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marissa [1.9K]
3 years ago
5

Knowing Newton’s 2nd Law, how would you rearrange it to solve for acceleration.

Physics
2 answers:
AysviL [449]3 years ago
8 0

Answer:

Force / mass

Explanation:

Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass

mezya [45]3 years ago
4 0
Newton’s 2nd : Force = rate of change of momentum
= (mv - mu) / t
= m (v-u) / t
= m a

( since a = (v-u)/t )

From F = m a then a= F/m
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option D is correct

Explanation:

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What is air masses? And 5 effect of it​
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Answer:

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5 0
3 years ago
As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. Th
NikAS [45]

Answer:

M = 0.730*m

V = 0.663*v

Explanation:

Data Given:

v_{bullet, initial} = v\\v_{bullet, final} = 0.516*v\\v_{paper, initial} = 0\\v_{paper, final} = V\\mass_{bullet} = m\\mass_{paper} = M\\Loss Ek = 0.413 Ek

Conservation of Momentum:

P_{initial} = P_{final}\\m*v_{i} = m*0.516v_{i} + M*V\\0.484m*v_{i} = M*V .... Eq1

Energy Balance:

\frac{1}{2}*m*v^2_{i} = \frac{1}{2}*m*(0.516v_{i})^2 + \frac{1}{2}*M*V^2 + 0.413*\frac{1}{2}*m*v^2_{i}\\\\0.320744*m*v^2_{i} = M*V^2\\\\M = \frac{0.320744*m*v^2_{i} }{V^2}  ....... Eq 2

Substitute Eq 2 into Eq 1

0.484*m*v_{i} = \frac{0.320744*m*v^2_{i} }{V^2} *V  \\0.484 = 0.320744*\frac{v_{i} }{V} \\\\V = 0.663*v_{i}

Using Eq 1

0.484m*v_{i} = M* 0.663v_{i}\\\\M = 0.730*m

7 0
3 years ago
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7 0
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