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andrew11 [14]
3 years ago
5

A 1400kg car is moving at a speed of 25m/s. How much KE does the car have?

Physics
1 answer:
Nady [450]3 years ago
6 0

Answer:

437500Joules

Explanation:

Kinetic energy=1/2mvsquare

1/2 x 1400 x 25 x25

kinetic energy= 437500Joules

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It is electronegativity the property of an atom which increases with its tendency to attract the electrons of an bond
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Need an explanation please. Brainliest will be awarded.
Maurinko [17]

We're adding two vectors here.  The first is 300 Newtons to the right, which we can write as (300, 0), meaning 300 to the right, 0 up.

The second is 300 at let's say a 45 degree angle down.  For the components we have an isosceles right triangle with hypotenuse 300, so the components are both magnitude 300/√2 = 150√2.  So we can write this vector (150√2, -150√2), the negative sign because it points down in the y direction.

Adding is componentwise.  The resulting force is (300+150√2, -150√2).

That has square magnitude

r² = (300+150√2)² + (-150√2)² = 150² ( (2+√2)² + (√2)² )

= 150²( (6 + 4√2) + 2)

= 300²(2+√2)

so

r = 300 √(2+√2) Newtons

That's the answer; I'm not sure if your class expects a calculator approximation, which is 554.3 Newtons.

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2 years ago
In a game of pool, the cue ball moves at a speed of 2 m/s toward the eight ball. When the cue ball hits the eight ball, the cue
Tomtit [17]

a)  p₀ = 1.2 kg m / s

b) p_f = 1.2 kg m / s  

c)    v_{2f} = 1.278 m/s

d)1.2482 =v_{2f} cos θ

e)  0.2736 =v_{2f}sin θ

g) θ = 12.36

<h3>What is momentum?</h3>

Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.

According to the question,

We define a system formed by the two balls, which are isolated and the forces during the collision are internal.

Hence , the momentum is conserved

a) The momentum of the system before the collision:

p_o = m v_1_0 + 0         p_o= 0.6 2         p_o = 1.2 kg m / s

b) The momentum of the system after the collision, as the system is isolated, the momentum is conserved so

p_f = 1.2 kg m / s

d. On X axis

p_ox = 1.2 kg m / s

p_{fx}= m v1f cos 20 + m v2f cos θ

p_o = p_f

1.2 = 0.6 (-0.8) cos 20+ 0.6v_{2f} cos θ

1.2482 =v_{2f} cos θ

e. On Y axis  

p_{oy} = 0

p_{fy}= mv_{1f}sin 20 + mv_{2f}cos θ

0 = 0.6 (-0.8) sin 20 + 0.6 v_{2f} sin θ

0.2736 =v_{2f}sin θ

Here,

g. we write our system of equations

0.2736 =v_{2f} sin θ

1.2482 = v_{2f} cos θ

0.219 = tan θ (divide)

θ = tan⁻¹ 0.21919

θ = 12.36

c. Now To find the velocity

0.2736 = v_{2f} sin θ

v_{2f}= 0.2736 / sin 12.36

v_{2f} = 1.278 m / s

Learn more about momentum here:

brainly.com/question/4956182

#SPJ1

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Buoyancy is a force that always acts in an upward direction exerted by a fluid on a body placed in the fluid

Hope this helps :)

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