Solution:
The relation between the potential difference and the electric field between the plates of the parallel plate capacitor is given by :
Differentiating on both the sides with respect to time, we get
Therefore, the rate of the electric field changes between the plates of the parallel plate capacitor is given by :
V/m-s
The dotted path is the path of the ball. it reaches it's maximum height at the top where vertical, y-velocity = 0
The initial y-velocity = 19sin(70°)
initial y-velocity = 17.85 m/s
Use one of the kinematic equations with velocity and time. No displacement because we don't want to worry about figuring that out.
v = u - gt
0 = 17.85 - 9.8t
-17.85 = -9.8t
17.85/9.8 = t
1.82 sec = t
Answer:
C. Sink until it reaches equilibrium and then remain at a constant depth.
Explanation:
An object immersed in a fluid experiences buoyant force. If the net buoyant force is greater than the net weigh of the object, the object will float.
If the net buoyant force is less than the net wight of the object, it will sink until a depth where the total weight of the object and the force due to the fluid above the object equals the net buoyant force at the bottom of the object (equilibrium), then the object remains at a constant depth.
Answer:
the attraction between N and S poles
Answer:
V2 = 1.33m/s
Explanation:
M1 = 30 ton
M2 = 90 ton
V1 = 4 m/s
V2 = ?
Assumption: momentum conserved, no friction
initial momentum = final momentum = 0
momentum : p = MV
(M1*V1) - (M2*V2) = 0
V2 = (30*4)/90 = 1.33m/s
