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andrew-mc [135]
3 years ago
13

Green light travels by what type of wave? (2 points) a Conductive b Electronic c Conducive d Electromagnetic

Physics
2 answers:
antiseptic1488 [7]3 years ago
8 0

Answer: d. Electromagnetic wave

Explanation:

Light is an electromagnetic wave, no matter is wavelength or color.

In this sense, the main characteristic of this type of wave is that it can propagate trhough vacumm, it is not necessary a medium. In addition, electromagnetic waves are transversal waves, this means the electric field oscillates in all normal directions to the direction of wave propagation.

Rom4ik [11]3 years ago
4 0

Answer:

d) Electromagnetic waves

Explanation:

As we know that electromagnetic waves are of 7 types as per their energy range

these are as following

1) Gamma Rays

2) X Rays

3) Ultraviolet rays

4) Visible light (VIBGYOR all colors)

5) Infrared waves

6) microwaves

7) Radio waves

Since all type of visible light exist in the range of electromagnetic waves

so we can say that Green light travels as per nature of electromagnetic waves

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Which phase of the Moon occurs when Earth, the Moon, and the Sun lie on the same line?
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If the wagon travels 18.75 m, what is the work done on the wagon
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If the wagon travels 18.75 m, then the work done on the wagon is

(18.75 m) x (the steady force applied to the wagon all the way, in Newtons) .

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3 years ago
Would the solar panel work under a fluorescent or halogen light? explain your response being sure to relate your observations to
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3 years ago
You are a member of an alpine rescue team and must get a box of supplies, with mass 2.20 kg , up an incline of constant slope an
a_sh-v [17]

Answer:

The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.

Explanation:

It is given that,

Mass of the box, m = 2.2 kg

The box is inclined at an angle of 30 degrees

Vertical distance, d = 3.1 m

The coefficient of friction, \mu=6\times 10^{-2}

Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.

KE=PE+W

\dfrac{1}{2}mv^2=mgh+W

W is the work done by the friction.

W=f\times d

f=\mu mg\ cos\theta

W=\mu mg\ cos\theta\times \dfrac{d}{sin\theta}

W=\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}mv^2=mgh+\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}v^2=gh+\dfrac{\mu gh}{tan\theta}

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So, the speed of the box is 8.19 m/s. Hence, this is the required solution.

8 0
2 years ago
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