1.47x10^5 Joules
The gravitational potential energy will be the mass of the object, multiplied by the height upon which it can drop, multiplied by the local gravitational acceleration. And since it started at the top of a 60.0 meter hill, halfway will be at 30.0 meters. So
500 kg * 30.0 m * 9.8 m/s^2 = 147000 kg*m^2/s^ = 147000 Joules.
Using scientific notation and 3 significant figures gives 1.47x10^5 Joules.
Simple cells have liquid chemicals, making it harder for it to carry. While as dry cells have no liquid chemicals, making it easier to carry.
Answer:
I hear points of low volume sound and points of high volume of sound.
Explanation:
This is because, since the two sources of sound have the same frequency and are separated by a distance, d = 10 mm, there would be successive points of constructive and destructive interference.
Since their frequencies are similar, we should have beats of high and low frequency.
So, at points of low frequency, the amplitude of the wave is smallest and there is destructive interference. The frequency at this point is the difference between the frequencies from both speakers. Since the frequency from both speakers is 400 Hz, we have, f - f' = 400 Hz - 400 Hz = 0 Hz. So, the volume of the sound is low(zero) at these points.
Also, at points of high frequency, the amplitude of the wave is highest and there is constructive interference. The frequency at this point is the sum between the frequencies from both speakers. Since the frequency from both speakers is 400 Hz, we have, (f + f') = 400 Hz + 400 Hz = 800 Hz. So, the volume of the sound is high at these points.
So, as you wander around the room, I should hear points of high and low sound across the room.
Answer:
The peak emf generated by the coil is 2.67 V
Explanation:
Given;
number of turns, N = 940 turns
diameter, d = 24 cm = 0.24 m
magnetic field, B = 5 x 10⁻⁵ T
time, t = 5 ms = 5 x 10⁻³ s
peak emf, V₀ = ?
V₀ = NABω
Where;
N is the number of turns
A is the area
B is the magnetic field strength
ω is the angular velocity
V₀ = NABω and ω = 2πf = 2π/t
V₀ = NAB2π/t
A = πd²/4
V₀ = N x (πd²/4) x B x (2π/t)
V₀ = 940 x (π x 0.24²/4) x 5 x 10⁻⁵ x (2π/0.005)
V₀ = 940 x 0.04524 x 5 x 10⁻⁵ x 1256.8
V₀ = 2.6723 V = 2.67 V
The peak emf generated by the coil is 2.67 V
The temperature of 20°C is equal to 68.0<span>°F</span>
