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3 years ago

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If a car increases its velocity from zero to 60 m/s in 10 seconds, its acceleration is A. 600 m/s2 B. 60 m/s2 C. 3 m/s2 D. 6 m/s

2

2 answers:

enot [183]3 years ago

7 0

Answer:

a

Explanation:

goblinko [34]3 years ago

5 0

Answer:

D. 6 m/s²

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (60 m/s − 0 m/s) / 10 s

a = 6 m/s²

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State Archimedes' principle

OlgaM077 [116]

Explanation:

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Thus,

<u>Weight of the displaced fluid = Weight of the object - Weight of object in fluid.</u>

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3 years ago

4. Define resistance and describe what would happen to a light bulb if the voltage increased but the resistance stayed the same.

Arlecino [84]

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3 years ago

Water from a fire hose is directed horizontally against at a rate of 50.0 kg/s and a speed of 42.0 m/s.

ss7ja [257]

Answer:

Force, |F| = 2100 N

Explanation:

It is given that,

Water from a fire hose is directed horizontally against at a rate of 50.0 kg/s, $\dfrac{m}{t}=50\ kg/s$

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The momentum is reduced to zero, final speed, v = 0

The relation between the force and the momentum is given by :

$F=\dfrac{p}{t}$

$F=\dfrac{mv}{t}$

$F=50\ kg/s\times 42\ m/s$

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3 years ago

How can you say that joule and Newton are derived units

maxonik [38]

Answer:

F = M a where M is acceleration and a is acceleration

a = x / s^2 = distance / time squared

The Newton is derived because mass, distance, and time are all fundamental units One would have to look at the fundamental requirements for these definitions, but they can all be repeated in a laboratory.

So the Newton is determined from these fundamental units and since the Joule equals Newton * Distance it is also derived from the fundamental units.

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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!!!

Elan Coil [88]

The spring constant is 181.0 N/m

Explanation:

We can solve the problem by applying the law of conservation of energy. In fact, the elastic potential energy initially stored in the compressed spring is completely converted into gravitational potential energy of the dart when the dart is at its maximum height. Therefore, we can write:

$\frac{1}{2}kx^2 = mgh$

where the term on the left represents the elastic potential energy of the spring while the term on the right is the gravitational potential energy of the dart at maximum height, and where

k is the spring constant of the spring

x = 2.08 cm = 0.0208 m is the compression of the spring

m = 12.3 g = 0.00123 kg is the mass of the dart

$g=9.8 m/s^2$ is the acceleration due to gravity

h = 3.25 m is the maximum height of the dart

Solving for k, we find:

$k=\frac{2mgh}{x^2}=\frac{2(0.00123)(9.8)(3.25)}{(0.0208)^2}=181.0 N/m$

Learn more about potential energy:

brainly.com/question/1198647

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3 years ago