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Sonbull [250]
3 years ago
11

Write the following number in scientific notation 156.60

Physics
1 answer:
Liula [17]3 years ago
8 0

Answer:

1.566 x 10^2

Move the decimal to where the number being multiplied by 10^x is greater than 1 but less than 10. Then multiply it by 10^x

X is the number of times you moved the decimal, so in this case it would be 10^2

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avanturin [10]
 <span>Cells undergo mitosis for three main reasons: 
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5 0
3 years ago
Read 2 more answers
which of the following locations has the largest electric field? A)0.4 cm from a +3.0 uC point charge B)0.2 cm frm a +1.5 uC poi
JulsSmile [24]
<span>Electric field is proportional to q/d^2, where q is the magnitude of the charge and d is the distance. Since all the given units are identical, we can just compare their relative magnitudes without calculating for the exact values.
A) 3/(0.4)^2 = 18.75
B) 1.5/(0.2)^2 = 37.5
C) 6/(0.4)^2 = 37.5
D) 3/(0.2)^2 = 75
Therefore, choice D has the largest electric field of all.
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7 0
3 years ago
If you lie on the ground at night with no cover, you get cold rather quickly. Much of this is due to energy loss by radiation. A
marin [14]

Answer:

301.48 J/s

Explanation:

We are given;

Temperature of the sky dropping to −40∘C: T_o = -40°C = -40 + 273 = 233 K

Temperature of your skin and clothes: T = 30°C = 30 + 273 = 303 K

Body surface area of human body is around 2 m². But here only half of the body is facing the sky, Thus Area is: A = 2/2 = 1 m²

To solve this, we will use the equation for thermal heat transfer known as the Stefan bolt Mann equation.

ΔQ/Δt = εσA(T⁴ - (T_o)⁴)

Where;

ΔQ/Δt is the rate at which you body loses energy by radiation

ε is the emissivity of the human body with a value of 0.97

σ is Stefan boltzmann constant with a value of 5.67 X 10^(-8) W/m².K⁴

Thus;

ΔQ/Δt = 0.97 × 5.67 X 10^(-8) × 1(303⁴ - 233⁴)

ΔQ/Δt = 301.48 J/s

7 0
3 years ago
A feather and a minivan are dropped vertically downward from a height of twenty meters and both are subject to air drag as they
Luda [366]

Answer:

maybe C i'm not 100% sure

I'm sorry if this didn't help

Explanation:

6 0
3 years ago
What force is needed to accelerate a child on a sled (total mass = 65.0 kg ) at 1.25 m/s2?
ratelena [41]
Given; Mass m = 65.0 Kg;   acceleration a = 1.25 m/s²

Required: Force F = ?

Formula: F =ma

               F = (65.0 Kg)(1.25 m/s²)

               F = 81.25 N
4 0
3 years ago
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