A. The acceleration during the slide is 6.86 m/s²
B. The time taken to slide until he stops is 1.2 s
<h3>How to determine the force of friction</h3>
- Mass (m) = 81.5 Kg
- Coefficient of friction (μ) = 0.7
- Acceleration due to gravity (g) = 9.8 m/s²
- Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 N
- Frictional force (F) =?
F = μN
F = 0.7 × 798.7
F = 559.09 N
<h3>A. How to determine the acceleration</h3>
- Mass (m) = 81.5 Kg
- Frictional force (F) = 559.09 N
- Acceleration (a) =?
a = F / m
a = 559.09 / 81.5
a = 6.86 m/s²
<h3>B. How to determine the time </h3>
- Initial velocity (u) = 8.23 m/s
- Final velocity (v) = 0 m/s
- Decceleration (a) = -6.86 m/s²
- Time (t) =?
a = (v – u) / t
t = (v – u) / a
t = (0 – 8.23) / -6.86
t = 1.2 s
Learn more about acceleration:
brainly.com/question/491732
#SPJ1
Answer:8.968 N-m
Explanation:
Given
Length of arm=0.152 m
Downward force=118 N
angle made by arm with vertical
Force can be divided into two components
It's sin component will contribute towards torque while cos component will not contibute
T=8.968 N-m
The option that takes place as water cycles from the bottom of the pot toward the top is that A. thermal energy is transferred.
As the pot gets warmer and warmer, the heat flows everywhere inside the pot, ultimately reaching the top, and heating the water at the top as well. There is no chemical energy here, and molecules don't gain thermal energy, it is just transferred to the top of the pot.
Hotter ocean tempatures mean more moisture in the dense air mass
Answer:
c. 48 cm/s/s
Explanation:
Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They determine that a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with a mass of 2M when acted upon by a net force of 2F?
from newtons second law of motion ,
which states that change in momentum is directly proportional to the force applied.
we can say that
f=m(v-u)/t
a=acceleration
t=time
v=final velocity
u=initial velocity
since a=(v-u)/t
f=m*a
force applied is F
m =mass of the object involved
a is the acceleration of the object involved
f=m*48.........................1
in the second case ;a mass of 2M when acted upon by a net force of 2F
f=ma
a=2F/2M
substituting equation 1
a=2(M*48)/2M
a=. 48 cm/s/s
