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3 years ago

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A coil of wire carrying a current may be used to create a magnetic field at the center of the coil. If the radius of the coil is

doubled while the number of windings and the current remain the same, then how does this change the strength of the magnetic field at the center?

1 answer:

hichkok12 [17]3 years ago

5 0

Answer:

Here magnetic field at center does not change, it remains constant .

Explanation:

The magnetic field at the center of the solenoid depends on only the current flowing through the wire and the number of turns of the coil around the solenoid .

Since magnetic field at the center of the solenoid is given by the expression

$B=\mu_{o}ni$

Here $\mu_{o}$ is permeability constant whose value is equal to $4\pi\times 10^{-7}\frac{H}{m}$ .

N is number of turns of the coil .

I is current flowing through the coil .

The field lines near the center of the solenoid are approximately parallel , indicating a nearly uniform magnetic field.

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Two bulbs marked 200 W-250 V and 100 W-250 V are joined in

lozanna [386]

Answer:

<em>P = 66.67 W</em>

Explanation:

<u>Joule Heating</u>

It's the process by which the electric current passing through a conductor produces heat.

Also known as Joule's first law or the Joule–Lenz law, states that the power of heating generated by an electrical conductor (P) is proportional to the product of its resistance (R) and the square of the current (I).

It can be described by the equation that follows:

$P = I^2.R$

Also, we can calculate the voltage V with the formula of Ohm's law:

$V = I.R$

Combining both equations, power can be related to the voltage:

$\displaystyle P=\frac{V^2}{R}$

Given the power and the voltage, the resistance can be calculated by solving for R:

$\displaystyle R=\frac{V^2}{P}$

There are two bulbs marked P=200W V=250V and P=100 W V=250.

The first bulb has a resistance of:

$\displaystyle R_1=\frac{250^2}{200}$

$\displaystyle R_1=312.5\Omega$

The first bulb has a resistance of:

$\displaystyle R_2=\frac{250^2}{100}$

$\displaystyle R_1=625\Omega$

When connected in series, the total resistance is

$R = R_1 + R_2=312.5\Omega+625\Omega$

$R=937.5\Omega$

The total power consumed when connecting them to a V=250 V supply is:

$\displaystyle P=\frac{250^2}{937.5}$

P = 66.67 W

4 0

3 years ago

A 230.-mL sample of a 0.240 M solution is left on a hot plate overnight; the following morning, the solution is 1.75 M. What vol

Gwar [14]

Answer:

The volume of water evaporated is 199mL

Explanation:

Concentration is calculated with the following formula

$C=\frac{n}{V}$

where n is the number of moles of solute and V is the volume of the solution (in this case is the same as the solvent volume) in liters.

So we isolate the variable n to know the amount of moles, using the volume given in liters

$230mL=0.23L$

$n=C*V=0.240 M*0.23L=0.055 mol$

Now, we isolate the variable V to know the new volume with the new concentration given.

$V=\frac{n}{C} =0.055mol/1.75M=0.031L=31mL$

Finally, the volume of water evaporated is the difference between initial and final volume.

$V_{ev}= V_{i} -V_{f} =230mL-31mL=199mL$

4 0

3 years ago

When an atom that has no charge looses two electrons it becomes a

alex41 [277]

Answer: it becomes a positive ion

Explanation:

So, when an atom loses 2 electrons there will be no change in the number of neutrons. Therefore, an isotope will not form. Thus, it is concluded that when an atom with no charge loses two electrons, it becomes a positive ion.

8 0

3 years ago

Read 2 more answers

A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac

Sedbober [7]

Answer:

v = 1.2 m/s

Explanation:

The wavelength of the waves is given as the horizontal distance between the crests:

λ = wavelength = 5.5 m

Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:

T = Time Period = 2(2.3 s) = 4.6 s

Now, the speed of the wave is given as:

$v = f\lambda$

where,

v= speed of wave = ?

f = frequency of wave = $\frac{1}{T} = \frac{1}{4.6\ s} = 0.217\ Hz$

Therefore,

$v = (0.217\ Hz)(5.5\ m)\\$

<u>v = 1.2 m/s</u>

5 0

3 years ago

1. In an experiment, a positively charged oil droplet weighing 6.5 x 10-15 N is held stationary

blagie [28]

The charge on the droplet must be $1.2\cdot 10^{-18} C$

Explanation:

In order for the oil droplet to be in equilibrium, the force of gravity acting on it (the weight, acting downward) must be equal to the electrical force acting upward.

The gravitational force is:

$F_g = 6.5 \cdot 10^{-15} N$

which is equivalent to the weight of the droplet.

The electric force is given by:

$F_E = qE$

where

q is the charge on the oil droplet

$E=5.3\cdot 10^3 N/C$ is the magnitude of the electric field

Since the two forces must be equal,

$F_G = F_E\\F_G = qE$

And solving for q,

$q=\frac{F_G}{E}=\frac{6.5\cdot 10^{-15} N}{5.3\cdot 10^3}=1.2\cdot 10^{-18} C$

Learn more about gravitational force and electric force:

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3 0

3 years ago