Incompletevquestion. However, I inferred from a general perspective about perpendicular lines.
<u>Explanation:</u>
Put simply, <u>perpendicular lines</u> are lines that are at right angles (90°) to each other. Thus, we could say based on this definition that for lines lll and mmm to be perpendicular they intersect and be at right angles (90°) to each other as <u>found on the attached image.</u>
Answer: 72m/1 min and 24 secs
Explanation:
He swims .75m/sec. im pretty sure i got it but let me know and ill help you out if its wrong
Answer:
D.300nm
Explanation:
Wavelength = Speed of light / Frequency of light.....
where the speed of light is...(3 × 10^8)
Wavelength = (3 × 10^8)/(1 × 10^15)
Wavelength = 3 × 10^-7
;Wavelength = 300 × 10^-9
Hence its....300 nm
Answer:
24,000 m
Explanation:
First find the rocket's final position and velocity during the first phase in the y direction.
Given:
v₀ = 75 sin 53° m/s
t = 25 s
a = 25 sin 53° m/s²
Find: Δy and v
Δy = v₀ t + ½ at²
Δy = (75 sin 53° m/s) (25 s) + ½ (25 sin 53° m/s²) (25 s)²
Δy = 7736.8 m
v = at + v₀
v = (25 sin 53° m/s²) (25 s) + (75 sin 53° m/s)
v = 559.0 m/s
Next, find the final position of the rocket during the second phase (as a projectile).
Given:
v₀ = 559.0 m/s
v = 0 m/s
a = -9.8 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (559.0 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 15945.5 m
The total displacement is:
7736.8 m + 15945.5 m
23682.2 m
Rounded to two significant figures, the maximum altitude reached is 24,000 m.
If the planet earth has no land masses, the idealized zonal
precipitation pattern would likely have regions that are wet in the equator and
there will be more of mid-latitudes if the earth has no land masses at all and
it does not exist.