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2 years ago

- Viscoelastic stress relaxation

Engineering

1 answer:

My name is Ann [436]2 years ago

5 0

Explanation:

The correct answers to the fill in the blanks would be;

1. Viscoelastic stress relaxation refers to scenarios for which the stress applied to a polymer must decay over time in order to maintain a constant strain. Otherwise, over time, the polymer chains will slip and slide past one another in response to a constant applied load and the strain will increase (in magnitude).

2. Viscoelastic creep refers to scenarios for which a polymer will permanently flow over time in response a constant applied stress.

The polymer whose properties have been mentioned above is commonly known as Kevlar.

It is mostly used in high-strength fabrics and its properties are because of several hydrogen bonds between polymer molecules.

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Air is compressed in an isentropic process from an initial pressure and temperature of P1 = 90 kPa and T1=22°C to a final pressu

ivolga24 [154]

Answer:

a) $T_2=569.35 K$

b)Work done per kg of air=196.84 KJ/Kg

Explanation:

Given: $\gamma =1.4$ for air.

$P_1=90 KPa ,T_=22^\circ C,P_2=900 KPa$

We know that

$\dfrac{T_2}{T_1}=\left (\frac{P_2}{P_1}\right )^{\dfrac{{\gamma-1}}{\gamma}}$

So $\dfrac{T_2}{295}=\left (\frac{900}{90}\right )^{\dfrac{{1.4-1}}{1.4}}$

$T_2=569.35 K$

(a) $T_2=569.35 K$

(b)Work for adiabatic process

W= $\frac{P_1V_1-P_2V_2}{\gamma -1}$

We know that PV=mRT for ideal gas.

W= $mR\frac{T_1-T_2}{\gamma -1}$

Now by putting values

work per kg of air= $0.287\times \frac{295-569.35}{1.4 -1}$

Work w=-196.84 KJ/Kg (Negative sign indicate work given to input.)

So work done per kg of air=196.84 KJ/Kg

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2 years ago

Basic output with variables (Java) This zyLab activity is intended for students to prepare for a larger programming assignment.

9966 [12]

Answer:

Explanation:

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2 years ago

What is an air mass?

kotegsom [21]

Answer:

An air mass is a body of air with horizontally uniform temperature, humidity, and pressure.

Explanation:

Because it is

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2 years ago

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A hollow pipe is submerged in a stream of water so that the length of the pipe is parallel to the velocity of the water. If the

Arlecino [84]

Answer:

increases by a factor of 6.

Explanation:

Let us assume that the initial cross sectional area of the pipe is A m² while the initial velocity of the water is V m/s², hence the flow rate of the water is:

Initial flow rate = area * velocity = A * V = AV m³/s

The water speed doubles (2V m/s) and the cross-sectional area of the pipe triples (3A m²), hence the volume flow rate becomes:

Final flow rate = 2V * 3A = 6AV m³/s = 6 * initial flow rate

Hence, the volume flow rate of the water passing through it increases by a factor of 6.

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3 years ago

Determine the initial void ratio, the relative density and the unit weight (in pounds per cubic foot) of the specimens for each

Elina [12.6K]

The initial void ratio is the parameter which is used to show the structural foundations for each specimen of sand so that the method and speed of compression would be measured.

Relative density is the mass per unit volume of each specimen of sand which is measured and it has to do with the relative ratio of the density of the sand.

Unit weight is the the exact weight per cubic foot of the sand which is measured.

Please note that your question is incomplete so I gave you a general overview to help you better understand the concept