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joja [24]
3 years ago
14

For an AC machine, what percentage of power is at the negative terminal?

Engineering
1 answer:
aivan3 [116]3 years ago
4 0
B, it should be somewhere in the 60s I believe
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Compute the number of kilo- grams of hydrogen that pass per hour through a 6-mm-thick sheet of palladium having an area of 0.25
nydimaria [60]

Answer:

The number of kilo- grams of hydrogen that pass per hour through this sheet of palladium is 4.1 * 10^{-3} \frac{kg}{h}

Explanation:

Given

x1 = 0 mm

x2 = 6 mm = 6 * 10^{-3} m

c1 = 2 kg/m^{3}

c2 = 0.4 kg/m^{3}

T = 600 °C

Area = 0.25 m^{2}

D = 1.7 * 10^{8} m^{2}/s

First equation

J = - D \frac{c1 - c2}{x1 - x2}

Second equation

J = \frac{M}{A*t}

To find the J (flux) use the First equation

J = - 1.7 * 10^{8} m^{2}/s * \frac{2 kg/m^{3}  - 0.4 kg/m^{3}}{0 - 6 * 10^{-3} } = 4.53 * 10^{-6} \frac{kg}{m^{2}s }

To find M use the Second equation

4.53 * 10^{-6} \frac{kg}{m^{2}s} = \frac{M}{0.25 m^{2} * 3600s/h}

M = 4.1 * 10^{-3} \frac{kg}{h}

4 0
3 years ago
The dry unit weight of a soil sample is 14.8 kN/m3.
Jlenok [28]

Answer:

See attachment for completed question

Explanation:

Given that; Brainly.com

What is your question?

mkasblog

College Engineering 5+3 pts

The dry unit weight of a soil sample is 14.8 kN/m3.

Given that G_s = 2.72 and w = 17%, determine:

(a) Void ratio

(b) Moist unit weight

(c) Degree of saturation

(d) Unit weight when the sample is fully saturated

See complete solving at attachment

4 0
3 years ago
When cutting a FBD through an axial member, assume that the internal force is tension and draw the force arrow _______ the cut s
shepuryov [24]

Problem-Solving Tip: When cutting an FBD through an axial member, assume that the internal force is tension and draw the force arrow directed away from the cut surface. If the computed internal force value turns out to be a positive number, then the assumption of tension is confirmed.

3 0
2 years ago
Consider tests of an unswept wing that spans the wind tunnel and whose airfoil section is NACA 23012. Since the wing model spans
Dominik [7]

Answer:

Check the explanation

Explanation:

to know the lift per unit span (N/m) that is expected to be measured when the wing attack angle is 4°

as well as the corresponding section lift coefficient and die moment coefficient .

Kindly check the attached image below to see the step by step explanation to the above question.

3 0
3 years ago
One kilogram of water fills a 150-L rigid container at an initial pressure of 2 MPa. The container is then cooled to 40∘C. Deter
lukranit [14]

The pressure of water is 7.3851 kPa

<u>Explanation:</u>

Given data,

V = 150×10^{-3} m^{3}

m = 1 Kg

P_{1} = 2 MPa

T_{2}  = 40°C

The waters specific volume is calculated:

v_{1} = V/m

Here, the waters specific volume at initial condition is v_{1}, the containers volume is V, waters mass is m.

v_{1} = 150×10^{-3} m^{3}/1

v_{1} = 0.15 m^{3}/ Kg

The temperature from super heated water tables used in interpolation method between the lower and upper limit for the specific volume corresponds 0.15 m^{3}/ Kg and 0.13 m^{3}/ Kg.

T_{1}= 350+(400-350) \frac{0.15-0.13}{0.1522-0.1386}

T_{1} = 395.17°C

Hence, the initial temperature is 395.17°C.

The volume is constant in the rigid container.

v_{2} = v_{1}= 0.15 m^{3}/ Kg

In saturated water labels for T_{2}  = 40°C.

v_{f} = 0.001008 m^{3}/ Kg

v_{g} = 19.515 m^{3}/ Kg

The final state is two phase region v_{f} < v_{2} < v_{g}.

In saturated water labels for T_{2}  = 40°C.

P_{2} = P_{Sat} = 7.3851 kPa

P_{2} = 7.3851 kPa

7 0
3 years ago
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