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3 years ago

Which option distinguishes the members of a software deployment process team most likely involved in the following scenario?

Engineering

1 answer:

Alchen [17]3 years ago

5 0

Answer:

A local bank, with several branches in three cities, requests changes to its mortgage calculation software.

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Joe is a chemical engineer whose plant discharges heavy metals into the local river. By the test authorized by the city governme

chubhunter [2.5K]

Answer:

B probably

Explanation:

Because the prompt doesn't specify what sort of violation it could be anything maybe when they release the metals during the day and so on.

5 0

2 years ago

Directions: Correct the errors.

schepotkina [342]

Answer:

1. I went to the library to study last night.

2.Helen borrowed my dictionary to look up the spelling of "occurred."

3.The teacher opened the window to let some fresh air into the room.

4..I came to this school to learn English.

5.I traveled to Osaka to visit my sister.

Explanation:

...

6 0

2 years ago

Consider a Carnot cycle executed in a closed system with 0.0058 kg of air. The temperature limits of the cycle are300 K and 940

cricket20 [7]

Answer:0.646 KJ

Explanation:

Using First law for cycle

$\sum Q=\sum W$

$\sum Q=Q_{1-2}+Q_{3-4}$

For adiabatic process heat transfer is zero and for isothermal process

d(Q)=d(W)

$Q_{1-2}=mRT_1\ln {\frac{P_1}{P_2}}$

Given $P_1=2000KPa$

$P_3=20KPa$

$\left (\frac{T_2}{T_3}\right )^{\frac{\gamma }{\gamma -1}$ = $\left (\frac{P_2}{P_3}\right )}$

$P_2=1089.06K$

$Q_{1-2}=0.0058\dot 0.287\dot 940\ln \frac{2000}{1089.06}$ = $0.95KJ$

$Q_{3-4}=mRT_2\ln {\frac{P_3}{P_4}}$

$\left (\frac{T_1}{T_4}\right )^{\frac{\gamma }{\gamma -1}$ = $\left (\frac{P_1}{P_4}\right )}$

Now we have to find $P_4=36.72KPa$

$Q_{3-4}=0.0058\dot 0.287\dot 300\ln \frac{20}{36.72}$ = $-0.30341KJ$

$Q_{net}=Q_{1-2}+Q_{3-4}$

$Q_{net}=0.95-0.303=0.646KJ$

$Q_{net}=W_{net}=0.646KJ$

7 0

3 years ago

For a 3-Phase, Wye connected system the Line to Line Voltage measures 12,470 Volts, the Phase current measures 120 Amps.

vladimir2022 [97]

Answer:

A. 7199.55 volts

B. 120A

Explanation:

In this question we have the

line voltage = VLL = 12470volts

Phase current = Iph = 120 amps

A.)

We are to calculate the line-to-neutral/phase voltage here

VLL = √3VL-N

VL-N = VLL/√3

VL-N = 12470/√3

This gives a line to neutral phase/voltage of 7199.55 volts.

We are to calculate the line current here:

In this connection, the line current and the phase current are equal

ILL = Iph = 120A

6 0

3 years ago

1. A diode laser has a band gap of eV0, where V0 is a voltage. The laser has an efficiency of 30%, meaning 30% of the power inpu

Savatey [412]

Answer:

Hence wavelength of the photons produced by the laser is

$\frac{hc}{eV_0}$

Explanation:

Given

Efficiency of laser - 30%

As we know

$eV_0 = \frac{hc}{\Lambda}$

h = plank's constant

c = speed of light

eV0 = band gap

Hence wavelength of the photons produced by the laser is

$\Lambda= \frac{hc}{eV_0}$

4 0

3 years ago