Answer:
S = 0.5 km
velocity of motorist = 42.857 km/h
Explanation:
given data
speed = 70 km/h
accelerates uniformly = 90 km/h
time = 8 s
overtakes motorist = 42 s
solution
we know initial velocity u1 of police = 0
final velocity u2 = 90 km/h = 25 mps
we apply here equation of motion
u2 = u1 + at
so acceleration a will be
a = 
a = 3.125 m/s²
so
distance will be
S1 = 0.5 × a × t²
S1 = 100 m = 0.1 km
and
S2 = u2 × t
S2 = 25 × 16
S2 = 400 m = 0.4 km
so total distance travel by police
S = S1 + S2
S = 0.1 + 0.4
S = 0.5 km
and
when motorist travel with uniform velocity
than total time = 42 s
so velocity of motorist will be
velocity of motorist = 
velocity of motorist = 
velocity of motorist = 42.857 km/h
If both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will: a) increase during a climb.
<h3>What is a
ram air input?</h3>
A ram air input can be defined as an air intake system which is designed and developed to use the dynamic air pressure that is created due to vehicular motion, or ram pressure, in order to increase the static air pressure within the intake manifold of an internal combustion engine of an automobile.
This ultimately implies that, a ram air input allows a greater mass-flow of air through the engine of an automobile, thereby, increasing the engine's power.
In conclusion, indicated airspeed will increase during a climb when both the ram air input and drain hole of the pitot system become blocked.
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Complete Question:
If both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will
a) increase during a climb
b) decrease during a climb
c) remain constant regardless of altitude change
The change in annual cost when Q is increased from 340 to 341 is -1.23 and the instantaneous rate of change when Q = 340 is -1.25
<h3>How to find the Instantaneous rate of change?</h3>
The annual inventory cost C for a manufacturer is given as;
C = (1012000/Q) + 7.5Q
where Q is the order size when the inventory is replenished.
Now, the change in C can be calculated by evaluating the cost function at Q = 340 and Q = 341
Change in C = [1,012,000/341 + 7.5*341] - [1,012,000/340 + 7.5*340] ≈ -1.23
Instantaneous rate of change in C is first order derivative C':
C'(Q) = -1,012,000/(Q²) + 7.5
C'(340) = -1,012,000/(340²) + 7.5 ≈ -1.25
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To solve this problem it is necessary to apply the concepts related to density in relation to mass and volume for each of the states presented.
Density can be defined as
Where
m = Mass
V = Volume
For state one we know that
For state two we have to
Therefore the total change of mass would be
Therefore the mass of air that has entered to the tank is 6.02Kg
Answer:
B. The thickness of the heated region near the plate is increasing.
Explanation:
First we know that, a boundary layer is the layer of fluid in the immediate vicinity of a bounding surface where the effects of viscosity are significant. The fluid is often slower due to the effects of viscosity. Advection i.e the transfer of heat by the flow of liquid becomes less since the flow is slower, thereby the local heat transfer coefficient decreases.
From law of conduction, we observe that heat transfer rate will decrease based on a smaller rate of temperature, the thickness therefore increases while the local heat transfer coefficient decreases with distance.
