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Airida [17]
3 years ago
6

Which set of points are collinear in the figure below?

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

zono eatas

Step-by-step explanation:

elledre de como dezie puaron

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What is the slope of the equation y=1/3x +5
iris [78.8K]

Answer:

\large\boxed{slope=\dfrac{1}{3}}

Step-by-step explanation:

The slope-intercept form of an eqaution of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the equation of a line:

y=\dfrac{1}{3}x+5

Therefore

\text{the slope}=\dfrac{1}{3}\\\\\text{y-intercept}=5

8 0
2 years ago
Read 2 more answers
Find the angle between u = (-2,-5) and v = (5,2)
OleMash [197]

The angle between u = (-2,-5) and v = (5,2) is 134 degrees approximately.

<u>Solution:</u>

Given, two vectors are u = (-2, -5) and v = (5, 2)

We have to find the angle between two vectors.

We know that,

a. b=\|a\| .\|b\| \times \cos \theta

where \theta is angle between vectors a and b

\text { Now vectors are }(-2 \vec{\imath}-5 \vec{\jmath}) \text { and }(5 \vec{\imath}+2 \vec{\jmath})

(-2 \vec{\imath}-5 \vec{\jmath}) \cdot(5 \vec{\imath}+2 \vec{\jmath})=\sqrt{(-2)^{2}+(-5)^{2}} \times \sqrt{5^{2}+2^{2}} \times \cos \theta

\text { since }\|a\|=\sqrt{x^{2}+y^{2}} \text { for } a=x \vec{\imath}+y \vec{\jmath}

\begin{array}{l}{-10-10=\sqrt{29} \times \sqrt{29} \times \cos \theta} \\\\ {-20=29 \times \cos \theta} \\\\ {\cos \theta=\frac{-20}{29}} \\\\ {\theta=\cos ^{-1} \frac{-20}{29}} \\\\ {\theta=133.60}\end{array}

Hence, the angle between given two vectors is 134 degrees approximately.

3 0
3 years ago
Here's a graph of a linear function. Write the
Kryger [21]

Answer:

<em>y = -3x+4</em>

<em />

Step-by-step explanation:

Slope intercept form of a line is given by  y = mx + b

Where

m is the slope

b is the y intercept.

To find m, we need to take any arbitrary 2 points and see how many units up/down and how many units right/left we need to go from one to another. <em>Basically change in y by change in x.</em>

<em />

Let's take 2 arbitrary points: (0,4)  &  (2,-2)

So we need to go -6 units from y = 4 to y = -2. We need to go 2 units from x = 0 to x = 2.

Hence slope is change in y by change in x, which is -6/2 = -3

b is the y-interceept, the place where it cuts the y axis. Looking at the graph, it is at y = 4

<em>Now we can write the equation as :</em>

<em>y = -3x+4</em>

5 0
3 years ago
Log(2t+4)=log(14-3t)
barxatty [35]

Answer:

t = 2

Step-by-step explanation:

2t + 4 = 14 - 3t

5t = 10

t = 2

Checking:

log(2(2) + 4)  =  log(8)

log(14 - 3(2))  =  log(8)

4 0
2 years ago
What is the solution to the equation x/3+x/6=7/2
Alchen [17]

Answer:

x = y

Step-by-step explanation:

x/3 + x/6 = 7/2

2x + x = 21

3x = 21

(divide 3 on both sides)

x = 7

5 0
2 years ago
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