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Aleks [24]
3 years ago
12

Find three consecutive even integers whose sum is −24

Mathematics
2 answers:
labwork [276]3 years ago
6 0

Answer: -10,-8,-6

Step-by-step explanation:

Let be:

 x, x+2 and  x+4 the three consecutive even integers whose sum is -24

Then, we can write this expression:

 x+(x+2)+(x+4)=-24

Now, we must solve for "x":

3x+6=-24\\\\3x=-24-6\\\\3x=-30\\\\x=\frac{-30}{3}\\\\x=-10

Then you get that the others integers are:

x+2=-10+2=-8

x+4=-10+4=-6

Therefore, the  three consecutive even integers whose sum is -24 are:

-10,-8,-6

Sophie [7]3 years ago
3 0

For this case we have that the sum of 3 consecutive integers is 24, if we represent by means of an equation we have:

x + (x + 2) + (x + 4) = - 24\\x + x + 2 + x + 4 = -24\\3x + 6 = -24\\3x = -24-6\\x = \frac {-30} {3}\\x = -10

Thus, the three consecutive numbers are:

x = -10\\x = -10 + 2= -8\\x = -10 + 4 = -6

Answer:

-10,-8,-6

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