A right triangle has a hypotenuse of 8 feet. One leg has a length of 5 feet. How long is the other leg?
2 answers:
THEOREM :
<u>Pythagorean theorem</u>:– In a right angled triangle, the sum of squares of two legs is equal to the square of hypotenuse.
ANSWER :
Let the other leg be p, by pythagorean theorem
p² = h² - b²
p² = (8)² - (5)²
p² = 64 - 25
p² = 39
p = √39 ft.
So, <u>Correct choice</u> - [B] √39 ft.
Answer:
B
Step-by-step explanation:
The formula a^2 + b^2 = c^2 can be used to find any of the legs of the triangle. a and b are legs of the triangle and c is the hypotenuse. We can substitute known values into the equation:
a^2 + b^2 = c^2
One leg is 5 so we can put that in as a. And c, the hypotenuse, is 8.
5^2 + b^2 = 8^2
Now solve for b.
First, square 5 and 8
25 + b^2 = 64
Subtract 25 from both sides
b^2 = 39
Take the square root of both sides
b = √39
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Answer:
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Step-by-step explanation:
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So let n be the smallest number. To have consecutive even integers each number goes up by 2 so n, n+2, n+4, n+6, n+8.
Therefore, n+n+2+n+4+n+6+n+8=290
5n+20=290
5n=270
n=54
Answer:
the answer is x because its small
Hey there, There are 2 ways1st way: Since there are 8 5 point problems, 38 - 8 = 30, will give you the 2 point problems.2nd way: 8 x 5 = 40 100 - 40 = 60 60 / 2 = 30 Thus there are 30, 2 point problems. Hope this helps :))~Top