A right triangle has a hypotenuse of 8 feet. One leg has a length of 5 feet. How long is the other leg?
2 answers:
THEOREM :
<u>Pythagorean theorem</u>:– In a right angled triangle, the sum of squares of two legs is equal to the square of hypotenuse.
ANSWER :
Let the other leg be p, by pythagorean theorem
p² = h² - b²
p² = (8)² - (5)²
p² = 64 - 25
p² = 39
p = √39 ft.
So, <u>Correct choice</u> - [B] √39 ft.
Answer:
B
Step-by-step explanation:
The formula a^2 + b^2 = c^2 can be used to find any of the legs of the triangle. a and b are legs of the triangle and c is the hypotenuse. We can substitute known values into the equation:
a^2 + b^2 = c^2
One leg is 5 so we can put that in as a. And c, the hypotenuse, is 8.
5^2 + b^2 = 8^2
Now solve for b.
First, square 5 and 8
25 + b^2 = 64
Subtract 25 from both sides
b^2 = 39
Take the square root of both sides
b = √39
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12(t + 2) + 4 ≥ - 8
12t + 24 + 4 ≥ - 8
12t + 28 ≥ - 8
12t ≥ - 8 - 28
12t ≥ - 36
t ≥ - 36 ÷ 12
t ≥ - 3
Solution:
t ≥ -3
(180-30)/2 would be the equation and the answer is 150/2
What do you need help with?
Answer:
145
Step-by-step explanation:
x = 2 , y= 5
Putting the values of x and y in the expression
=3(2) (5)^2-5
=3(2)(25)-5
=150 -5
=145
