distance of each pan from the center or fulcrum is given as

now if dishonest shopkeeper shifted it by 0.633 cm from center
so distance on each side is given as


now the weight is balance as


now we will have

now we can find the percentage change as


Answer:
The net torque about the pivot is and the answer is 'c'
c. 
Explanation:

The torque is the force apply in a distance so it is the moment so depends on the way to be put it the signs so:





Now to find the net Torque is the summation of both torques


The answer is vaporization, then condensation.
Here is a set of flash card that can help with this subject.
All forces must add up to zero. See pictures below.