Answer:
Magnitude of the force is 4350N
Explanation:
As the woman accelerates at a distance of 22 m to go from rest to 62.5 m / s, we can use the kinematics to find the acceleration
v² = v₀² + 2 a x
v₀ = 0
a = v² / 2x
a = 62.5²/(2 × 22)
a = 88.78m/s²
the time you need to get this speed
v = v₀ + a t
t = v / a
t = 62.5 / 88.78
t = 0.704s
Let's caculate the magnitude of the force
F = ma
= 49 × 88.78
= 4350.22
≅ 4350N
Magnitude of the force is 4350N
t = 1,025 s
a = 55.43 m / s²
Answer:
2.4583 ± 0.0207 seconds
Explanation:
The time period of a pendulum is approximately given by the formula ...
T = 2π√(L/g)
The maximum period will be achieved when length is longest and gravity is smallest:
Tmax = 2π√(1.51/9.7) ≈ 2.47903 . . . seconds
The minimum period will be achieved for the opposite conditions: minimum length and maximum gravity:
Tmin = 2π√(1.49/9.9) ≈ 2.43756 . . . seconds
If we want to express the uncertainty using a symmetrical range, we need to find half their sum and half their difference.
T = (2.47903 +2.43756)/2 ± (2.47903 -2.43756)/2
T ≈ 2.4583 ± 0.0207 . . . seconds
__
We have about 2+ significant digits in the given parameters, so the time might be rounded to 2.46±0.02 seconds.
Answer:
7. 2 kg
8. 0.5 kg
9. 4 kg
Explanation:
The equation is F=MA
where F is force in Newtons
M is mass in kg
A is acceleration in m/s^2
for each you substitute in the F and A, and you are finding M. Meaning you divide F by A.
M = F/A
6/3 = 2
6/12 = 0.5
20/5 = 4
Answer:
71 cm
Explanation:
Every 100 mm is equal to 10 cm. Hope this helps!
Answer:
98.12 m
Explanation:
Initial speed(v) = 25.0 m/s
Coefficient of static friction (u) = 0.650
The minimum value of the coefficient of kinetic friction should be the coefficient of static friction.
Kinetic friction is given as
umg = ma (a is the required acceleration)
We then have
a = -ug
= -(0.65*9.8)
= -6.37 m/s^2
The shortest distance d is obtained by
d = (V^2 - v^2)/ 2a
V = 0 m/s (final velocity)
d = (0 - 25^2) / 2(-6.37)
d = -625/-6.37
d = 98.12 m
