I believe the answer is the poles of the magnet.
As given:
Initial moles of P taken = 2 mol
the products are R and Q
at equilibrium the moles of
R = x
total moles = 2 + x/2
Let us check for each reaction
A) P <-> 2Q+R
Here if x moles of P gets decomposed it will give 2x moles of Q and x moles of R
So at equilibrium
moles of P left = 2- x
moles of Q = 2x
moles of R = x
Total moles = (2-x) + 2x + x = 2 +2x
B) 2P <-> 2Q+R
Here x moles of P will give x moles of Q and x/2 moles of R
So at equilibrium
moles of P left = 2- x
moles of Q = x
moles of R = x/2
Total moles = (2-x) + x + x/2 = 2 + x/2
C) 2P <-> Q+R
Here x moles of P will give x/2 moles of Q and x/2 moles of R
So at equilibrium
moles of P left = 2- x
moles of Q = x /2
moles of R = x/2
Total moles = (2-x) + x + x = 2
D) 2P <-> Q+2R
Here x moles of P will give x/2 moles of Q and x moles of R
So at equilibrium
moles of P left = 2-x
moles of Q = x/2
moles of R = x
Total moles = (2-x) + x/2 + x = 2 + x/2
Hello there!
The nuclear emanations 1, 2 and 3 are called, respectively:
1) Alpha, beta and gamma
Alpha Radiation consists of two protons and two neutrons, as protons are positive particles, they will be attracted to the negatively charged plate.
Beta Radiation is composed of a high-energy electron. As electrons are negative particles, they will be attracted to the positively charged plate.
Gamma Radiation is composed or photons. Photons don't have charge or mass, and they will not be attracted to the charged plates. This kind of radiation is more penetrating than the other two.
Have a nice day!
Answer :
The correct answer is %IC = 10 % and bond is covalent bond with slight polarity.
<u>Percent Ionic Character :</u>
It is defined as percent of ionic character present in a polar covalent bond . The formula of % ionic character (%IC) is given as follows :

Where Xa = Electronegativity of A atom and Xb = Electronegativity of B atom
Given : Molecule is TiAl₃
Electronegativity of Ti = 2.0
Electronegativity of Al = 1.6 ( From image shared )
Plug the value in above formula :



Value of e⁻¹ = 0.90
Percent ionic character = 1 - 0.90 * 100
Percent Ionic character = 10 %
<u>Since the % IC is 10 % , which is very less comparatively , hence the bond is covalent and very less polar .</u>