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STALIN [3.7K]
3 years ago
15

Aluminium oxide has a very high melting point (2072 degrees C) while carbon dioxide has a very low boiling point (-57 degrees C)

. Explain this difference clearly.
Please help I don’t get what it’s asking!!!
Chemistry
1 answer:
____ [38]3 years ago
5 0

Answer:

Well, Aluminum Oxide has a very high melting point. Carbon dioxide has a very low boiling point.

Explanation:

They are both talking about different things, melting and boiling. Aluminum Oxide's melting point is much higher then carbon dioxide's melting point. Hope this help, and good luck on your assignment (if one)

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What is the weight in grams of 3.36 × 10Ƴ molecules of copper sulfate (CuSOÁ)?
spin [16.1K]
Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
         ? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

hope this helps!
6 0
3 years ago
Please help asap thank you.
Aleks [24]

Answer:

a)0.816g/l

b)0.241g/l

8 0
2 years ago
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Marysya12 [62]

Answer:

here's is ur answer in attachment

Explanation:

mark it brainliest if it helps you ❤️

3 0
3 years ago
Which types of changes must follow the law of conservation of mass?
Elis [28]

Answer: both

Explanation:

6 0
3 years ago
The reaction 2NO(g)+Cl2(g)→2NOCl(g) is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate o
Luba_88 [7]

Answer : The rate of change of the total pressure of the vessel is, 10.5 torr/min.

Explanation : Given,

\frac{d[NO]}{dt} =21 torr/min

The balanced chemical reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)

The rate of disappearance of NO = -\frac{1}{2}\frac{d[NO]}{dt}

The rate of disappearance of Cl_2 = -\frac{d[Cl_2]}{dt}

The rate of formation of NOCl = \frac{1}{2}\frac{d[NOCl]}{dt}

As we know that,

\frac{d[NO]}{dt} =21 torr/min

So,

-\frac{d[Cl_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[Cl_2]}{dt}=\frac{1}{2}\times 21torr/min=10.5torr/min

And,

\frac{1}{2}\frac{d[NOCl]}{dt}=\frac{1}{2}\frac{d[NO]}

\frac{d[NOCl]}{dt}=\frac{d[NO]}=21torr/min

Now we have to calculate the rate change.

Rate change = Reactant rate - Product rate

Rate change = (21 + 10.5) - 21 = 10.5 torr/min

Therefore, the rate of change of the total pressure of the vessel is, 10.5 torr/min.

8 0
3 years ago
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