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3 years ago

How do you graph and answer this question

Mathematics

2 answers:

lakkis [162]3 years ago

8 0

THIS ANSWER IS (-2,0)

HOPE THAT HELPS

julia-pushkina [17]3 years ago

5 0

(-2.0) i hope it help

You might be interested in

Write an absolute value equation to satisfy the given solution set shown on a number line.

aivan3 [116]

Answer: IX - 4I ≤ 4

Step-by-step explanation:

In the numer line we can see that our possible values of x are in the range:

0 ≤ x ≤ 8

And we want to find an absolute value equation such that this set is the set of possible solutions.

An example can be:

IX - 4I ≤ 4

To construct this, we first find the midpoint M of our set, in this case is 4.

Then we write:

Ix - MI ≤ IMI

Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the < > signs.

8 0

3 years ago

The bells are adding a new room to their house. The room will be a cube with volume 8,000 ft^3. They are going to put in hardwoo

Mandarinka [93]

Answer:

$4000

Step-by-step explanation:

Given that :

Volume of cube = 8000 ft³

Charge per ft² = $10

Recall, volume of a cube = a³

Where a = edge

Hence,

a³ = 8000

Take the cube root of both sides

a = 20

Hence,

Volume = 20 * 20 * 20

The Area of the floor will be :

20 * 20 = 400 ft²

If charge per ft² = $10

400 ft² = ($10 * 400) = $4000

8 0

2 years ago

Question 17 of 25

belka [17]

Answer:

Step-by-step explanation:

10 ÷ 8

=0.8

≈1% probability

4 0

3 years ago

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

4 0

3 years ago

Read 2 more answers

Help! Please? Dont understand

xz_007 [3.2K]

Answer:

Step-by-step explanation:

Answered by Gauthmath

4 0

3 years ago

Read 2 more answers