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4 years ago

I NEED HELP LIKE RN!?!?

Mathematics

1 answer:

Artyom0805 [142]4 years ago

8 0

17. x=360-320 x=40

18. x=360-275 x=85

19. x=360-290 x=70

20. x=360-260 x=100

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1) The ages of trees in a forest are normally distributed with a mean of 25 years and a standard deviation of 5 years. Using the

8090 [49]

Answer:

1) 68%

2) 68%

Step-by-step explanation:

<h2>1) The ages of trees</h2>

We know the mean and the standard deviation.

The mean is:

$\mu=25$

The standard deviation is:

$\sigma=5$

The Z-score formula is:

$Z = \frac{x-\mu}{\sigma}$

For x=20 the Z-score is:

$Z_{20}=\frac{20-25}{5}=-1$

For x=30 the Z-score is:

$Z_{30}=\frac{30-25}{5}=1$

Then we look for the percentage of the data that is between $-1$ deviations from the mean.

According to the empirical rule 68% of the data is less than 1 standard deviations of the mean. This means that 68% of the trees are between 20 and 30 years old

<h2>2) Pizza delivery </h2>

First we calculate the Z-scores

We know the mean and the standard deviation.

The mean is:

$\mu=27$

The standard deviation is:

$\sigma=3$

The z-score formula is:

$Z = \frac{x-\mu}{\sigma}$

For x=24 the Z-score is:

$Z_{24}=\frac{24-27}{3}=-1$

For x=30 the Z-score is:

$Z_{30}=\frac{30-27}{3}=1$

Then we look for the percentage of the data that is between $-1$ deviations from the mean.

According to the empirical rule 68% of the data is less than 1 standard deviations of the mean. This means that 68% of pizzas are delivered between 24 and 30 minutes

8 0

3 years ago

The attractive electric force between point charges q and -2q has a magnitude of 2.2 N when the separation

swat32

Answer:

The Magnitude of charge = q = 15.47 micro coulomb

Step-by-step explanation:

The attractive force between two points q and - 2 q = F = 2.2 Newton

The separation between two charges = 1.4 meters

Now from Coulomb's law = F = $(k \frac{q1 q2}{r^{2}})$ where k= $9 \times 10^{9}$ $\frac{N m^{2}}{c^{2}}$