Answer:
8
Step-by-step explanation:
1/4 times 8 is 2
It is 28 i think been 3 year since i did this
Solution :
Mean time for an automobile to run a 5000 mile check and service = 1.4 hours
Standard deviation = 0.7 hours
Maximum average service time = 1.6 hours for one automobile
The z - score for 1.6 hours = ![$\frac{1.6-1.4}{0.7 / \sqrt{50}}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1.6-1.4%7D%7B0.7%20%2F%20%5Csqrt%7B50%7D%7D%24)
= 2.02
Now checking a normal curve table the percentage of z score over 2.02 is 0.0217
Therefore the overtime that will have to be worked on only 0.217 or 2.017% of all days.