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grin007 [14]
3 years ago
8

H​2 ​​ and O2 ​​ react to produce H​2O. What is the mass of H2​​O produced when 0.73 g of H​2 ​​ completely reacts with 3.28 g o

f O2 ​​ ?
Chemistry
1 answer:
Slav-nsk [51]3 years ago
4 0
Hydrogen reacts with oxygen based on the following equation:
2 H2<span> + O</span>2<span> → 2 H</span>2<span>O
</span>
From the periodic table:
molar mass of hydrogen = 1 gram
molar mass of oxygen = 16 grams

From the balanced equation above, we can find that:
4 grams of hydrogen react with 32 grams of oxygen to produce 36 grams of water.

This means that: 0.73 grams of hydrogen require (0.73x32) / 4 = 5.84 grams of oxygen to react with.
Since only 3.28 grams of oxygen are reacting, this means that oxygen is our limiting reagent and that the reaction would stop once the amount of oxygen is consumed.

So, we will base our calculations on oxygen.
mass of water produced from 3.28 grams of oxygen can be calculated as follows:
mass of water = (3.28 x 36) / 32 = 3.69 grams
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Answer:

The volume will goes to decrease.

Explanation:

The given problem will be solved through the Boyle's law,

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Mathematical expression:

P₁V₁ = P₂V₂

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when pressure is going to increase the volume will goes to decrease and vice versa.

Consider the initial volume is 10 L at initial pressure of 15 atm when pressure is increased to 30 atm the volume will be,

Now we will put the values in formula,

P₁V₁ = P₂V₂

15 atm × 10 L = 30  atm × V₂

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6 0
3 years ago
Now consider the reaction when 45.0 g NaOH have been added. What amount of NaOH is this, and what amount of FeCl3 can be consume
gayaneshka [121]

The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.

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The molar mass of NaOH = 40 g/mol

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= 45 / 40

= 1.125

Thus, 1.125 mol NaOH is available

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1.125 moles of NaOH will react with x moles of FeCl₃

x = 1.125 / 3

x = 0.375 mol

0.375 mol FeCl₃ can take part in reaction

The molar mass of FeCl₃ is 162 g/mol

The mass of FeCl₃ = moles × mass

= 0.375 × 162

= 60.75 g

Thus, the amount of FeCl₃, which can be consumed is 60.75 g

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d1i1m1o1n [39]

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