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jekas [21]
2 years ago
9

Which is NOT true of ionic bonding?

Chemistry
1 answer:
WARRIOR [948]2 years ago
6 0

Answer:

D is wrong

Explanation:

it doesn't involves any kind of sharing of electrons

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6. A balloon filled with air has a volume of 3.25 L at 30°C. It is placed in a freezer at
Viefleur [7K]

Answer:

2.82 L

T₁ = 303 K

T₂ = 263 K

The final volume is smaller.

Explanation:

Step 1: Given data

  • Initial temperature (T₁): 30 °C
  • Initial volume (V₁): 3.25 L
  • Final temperature (T₂): -10 °C
  • Final volume (V₂): ?

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

T₁: K = 30°C + 273.15 = 303 K

T₂: K = -10°C + 273.15 = 263 K

Step 3: Calculate the final volume of the balloon

Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 3.25 L × 263 K/303 K = 2.82 L

7 0
2 years ago
What are some similarities and differences between physical and chemical weathering
mote1985 [20]
Similarities:
they both made sediment into soil
they both form the earth
they both made sediments have cracks

differences:
physical is reliant usually on contact with atmospheric condition

chemical transforms rocks into sediments while physical only breaks it down

chemical uses chemical reactions


(a brainliest would be appreciated)
3 0
3 years ago
Read 2 more answers
It takes 5.54 mL of a 2.18 M NaOH solution to neutralize 6.19 mL of an HCl solution. What is the concentration of the HCl soluti
svetlana [45]

Answer:

2 M

Explanation:

NaOH + HCl --> NaCl + H2O,

5.54 mL = .00545 L,

If we consider 2.18 M, M [molarity] = mol/L, so we have 2.18 mol/L. From this we can get the moles of NaOH.

.00545 L *  2.18 mol/L ≈ .0121 mol

The concentration of HCl can be found from the following:

.0121 mol = .00619(x) [where x = concentration of HCl]

x = 1.955 M ≈ 2 M

We equate the two as we require the same amount in order to neutralize the base.

5 0
3 years ago
How would you prepare a 1 L solution of 3 M Mgo?
Alborosie

Answer: We need to 120 g of MgO in the beaker and add enough water to reach the 1 L mark.​

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of MgO = \frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{40g/mol}

Now put all the given values in the formula of molality, we get

3M=\frac{x}{40g/mol\times 1L}

x=120g

Therefore, we need to 120 g of MgO in the beaker and add  enough water to reach the 1 L mark.​

3 0
3 years ago
C. 6.726 x 104 g =<br><br> standard notation
Vlad [161]

Answer:

6.99504 x 10^{2}

6 0
3 years ago
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