125 cm^3 ——————)-)-()-)))-
Answer:
According to wavelengths in descending order: C, B, D, E and A
According to frequencies in descending order: A, E, D, B and C
According to speeds in vacuum: A =B =C =D =E
Explanation:
in the EM spectrum, radio waves have the longest wavelength while gamma rays have the shortest wavelength.
All EM waves travel with the same speed of
in a vacuum.
Answer:
c
Explanation:
the loud noise can reduce the quality of the analog signal
Answer:
The displacement of the air drop after 3 second is 18.27 m.
Explanation:
Mass of the rain drop = m = 
Weight of the rain drop = W
Duration of time = t = 3 seconds

Drag force on rain drop = 

Motion of the rain drop:

Net force on the rain drop , F= W - D




v = 12.18 m/s
Initial velocity of the rain drop = u = 0 (since, it is starting from rest)
v=u+at (First equation of motion)


(second equation of motion)

s = 18.27 m
The displacement of the air drop after 3 second is 18.27 m.
For the answer to the question above, each horse's force forms a right angle triangle with the barge and subtends an angle of 60/2 = 30°. The resultant in the direction of the barge's motion is:
Fx = Fcos(∅)
We can multiply this by 2 to find the resultant of both horses.
Fx = 2Fcos(∅)
Fx = 2 x 720cos(30)
Fx = 1247 N