1. A 9000 kg van was stopped at a traffic light when it rear-ended with an 850 compact car moving to the east at a velocity of 5
1 answer:
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Let be the average acceleration over the first 2.46 seconds, and
the average acceleration over the next 6.79 seconds.
At the start, the car has velocity 30.0 m/s, and at the end of the total 9.25 second interval it has velocity 15.2 m/s. Let be the velocity of the car after the first 2.46 seconds.
By definition of average acceleration, we have
and we're also told that
(or possibly the other way around; I'll consider that case later). We can solve for in the ratio equation and substitute it into the first average acceleration equation, and in turn we end up with an equation independent of the accelerations:
Now we can solve for . We find that
In the case that the ratio of accelerations is actually
we would instead have
in which case we would get a velocity of
Answer:
The acceleration that earth experiences due to gravitational pull is = 9.81 .
Explanation:
The acceleration that earth experiences due to gravitational pull is called the acceleration due to gravity. its value is 9.81 and its unit is .
When the object move upwards than in that case the earth gravitational force pulls down the body.
The formula of force due to gravity on the body is given as
F = mg
where g = acceleration due to gravity.
Due to this acceleration the body falls upon the surface of the earth.