a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.
from above statement we got
height = 78.4 m
since the ball is thrown, so its vertical velocity would be zero
u = 0
taking g = 9.8m/s^2
now, using the equation of motion
h = ut + gt^2/2
now putting all the values in it
we got ,
78.4 = 9.8 * t^2/ 2
by solving we got,
t = 4 sec
b) now, since along the horizontal , no force acting and accelaration is zero so
R = ut , R is RANGE
R = 5 * 4
range = 20 m
c) vertical components of the stone’s velocity just before it hits the ground = v sin θ =
horizontal components of the stone’s velocity just before it hits the ground = v cos θ
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Mass is an intrinsic property of the rock. The mass doesn't care where it is, and it makes no difference where the rock happens to be at the moment ... its mass doesn't change.
17kg of mass is 17kg . If it's 17kg on the moon, it's <em>17kg</em> on Earth.
B. number of oscillations in a given period of time.
The kinetic energy of the ejected electrons will be 2782.5 ×10⁻²² eV.
<h3>What is threshold frequency?</h3>
The threshold frequency of incoming radiation is the lowest frequency at which photoelectric emission or electron emission is impossible.
The threshold frequency is the light frequency that causes an electron to dislodge and emit from the metal's surface.
From the photoelectric effect, the equation obtained as;
Hence,the kinetic energy of the ejected electrons will be 2782.5 ×10⁻²² eV.
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Answer: 4.6 years
Explanation:
According to Kepler’s Third Law of Planetary motion <em>“The square of the orbital period 
of a planet is proportional to the cube of the semi-major axis 
(size) of its orbit”:
</em>
<em />
(1)
However, if is measured in Earth years, and is measured in astronomical units (unit equivalent to the distance between the Sun and the Earth), equation (1) becomes:
(2)
Knowing 
and isolating from (2):
(3)
(4)
Finally:
This is Ceres' orbital period
