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sukhopar [10]
2 years ago
14

1. A 9000 kg van was stopped at a traffic light when it rear-ended with an 850 compact car moving to the east at a velocity of 5

m/sec. What would be the velocity of the entangled cars after collision?
Physics
1 answer:
____ [38]2 years ago
8 0

Answer:

1.785 m/s

Explanation:

The momentum can be calculated using the expression below

M1 *V1 + M2 * V2 = (M1+M2) V3

M1= mass of van=9000 kg

M2= mass of car= 850kg

V3= velocity of entangled car

V1= Velocity of the van= 0

V2= velocity of the car= 5 m/ s

Substitute the values

(900×0) + (500×5)=( 900+500)× V3

2500=1400 V3

V3=2500/1400

V3= 1.785 m/s

Hence, velocity of the entangled cars after collision is 1.785 m/s

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You release a block from the top of a long, slippery inclined plane of length l that makes an angle θ with the horizontal. The m
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Answer:

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speed     V = √(2g L sin θ)

Explanation:

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Where Y give us a constant initial energy from which the differences are measured, for general simplicity it is selected as zero, Yo= 0

What we find an expression for height, let's use trigonometry

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2. The mechanical energy of the system is conserved, so we will write the mechanical energy at two points the highest and the lowest

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Lower              Em = K

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3 years ago
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Answer:

a) d = 7.62 10⁻⁶ m, b)    l = 3.25 10⁴ m

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now we can find the cable diameter with the density equation

      A = m / density l

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      A = 4,557 10⁻¹¹ m²

the area of ​​the circle is

      A = π r² = π d² / 4

      d = √ (4A /π)

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