Answer:
Approximately 
.
Explanation:
By the Impulse-Momentum Theorem, the change in this woman's momentum will be equal to the impulse that is applied to her.
The momentum 
of an object is equal to the product of its mass 
and velocity 
. That is: 
.
Let 
and 
represent the velocity of the woman before and after the landing. Let represent the woman's mass.
- The woman's momentum before the landing would be
. - The woman's momentum after the landing would be
.
Therefore, the change in this woman's momentum would be:
.
On the other hand, impulse is equal to force multiplied by the duration of the force. Let 
represent the average force on the woman. The impulse on her during the landing would be 
.
Apply the Impulse-Momentum Theorem.
- Impulse:
. - Change in momentum:
.
Impulse is equal to the change in momentum:
.
After landing, the woman comes to a stop. Her velocity would become zero. Therefore, 
.
.
Answer:
A
Explanation:
Momentum conservation will cause 0.08kg to move to the west (opposite of 0.02 kg).
and because both are at the same height above the ground, they will take the same time to reach the ground.
The speed of 0.08kg will be less than 0.02 kg, let v be the speed of 0..02kg, then speed of 0.08kg V is
0.02v - (0.08)V = 0
V = 0.02 v/ 0.08 = v/4
The speed of 0.08 kg = v/4
The speed of 0.08 kg is less than 0.02kg.
So 0.02kg strikes the ground farther from the launch point than does the 0.08 kg
The answer is B) They do NOT require a medium to travel.
Answer:
7. Net constant force down the ramp
Explanation:
After the car is released and starts moving up the ramp, the only force that is applied on the car is weight because of the gravity, we were told that the friction force is neglected. the force because of the weight is given by:
where θ is the angle of the ramp.
as you can see those values won't change, so the force remains constant down the ramp.
I would say your answer to this question would be D
