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Basile [38]
4 years ago
6

A block of mass 2.0kg resting on a smooth horizontal plane is acted upon simultaneously by two forces, 10N due to north and 10n

due to east. the magnitude of the acceleration produced by the forces on the block is what

Physics
1 answer:
Lerok [7]4 years ago
5 0

In triangle ABC

AB = hypotenuse = Net force = R

Using Pythagorean theorem

AB=\sqrt{AC^{2}+BC^{2}}

R=\sqrt{10^{2}+10^{2}}

R = 14.1 N

m = mass of the block = 2.0 kg

a = acceleration of the block = ?

Magnitude of the acceleration is given as

a=\frac{R}{m}\\

a=\frac{14.1}{2}\\

a = 7.05 m/s²


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How much work is done when you push a crate horizontally with 130
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3 years ago
Monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00 m away, the distance from the ce
jasenka [17]

Answer:

\lambda= 506.25 nm

Explanation:

Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.

This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:

y=\frac{m \lambda D}{a}

Where:

y=Displacement\hspace{3}from\hspace{3} the\hspace{3} centerline \hspace{3}for \hspace{3}minimum\hspace{3} intensity =1.35mm\\\lambda=Light\hspace{3} wavelength \\D=Distance\hspace{3}between\hspace{3}the\hspace{3}screen\hspace{3}and\hspace{3}the\hspace{3}slit=2m\\a=width\hspace{3}of\hspace{3}the\hspace{3}slit=0.750mm\\m=Order\hspace{3}number=1

Solving for λ:

\lambda=\frac{y*a}{mD}

Replacing the data provided by the problem:

\lambda=\frac{(1.35\times 10^{-3})*(0.750\times 10^{-3})}{1*2} =5.0625\times 10^{-7}m =506.25nm

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3 years ago
Need help 8th grade science test need help
jolli1 [7]
ANSWER: d, average speed
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2 years ago
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