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alina1380 [7]
3 years ago
6

What is 5292cm rounded to the nearest thousandth

Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0

There's no decimal so this doesn't need to be rounded.

If you mean 5.292cm, that's already rounded, as the thousandth place is the third place.

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In 1995, the standard bus fare in Chicago was $1.65. In 2008, the standard bus fare was $2.50. Find the percent
uranmaximum [27]

Answer: 85%

Step-by-step explanation:

3 0
3 years ago
Problem 8) In the diagram, RQ ⊥ PQ, m∠QPS = 32°, m∠RPS = 24°, and PQ = 14.Find RS to the nearest tenth of a unit. Image is provi
Sav [38]

Since S is a point on the segment QR, then:

QS+SR=QR

Use the diagram and trigonometric relationships to find the value of QS and QR. Then, use the above equation to solve for SR.

In the right triangle PQS, the side QS is opposite to the angle of 32º, and the side PQ is adjacent to the angle of 32º. Then, use the tangent trigonometric function to relate PQ to QS:

\tan\left(32º\right)=\frac{QS}{PQ}

Isolate QS and replace PQ=14:

\begin{gathered} \Rightarrow QS=PQ\cdot\tan\mleft(32º\mright) \\ \operatorname{\Rightarrow}QS=14\tan\mleft(32º\mright) \end{gathered}

On the other hand, notice that the side QR in the right triangle PQR is opposite to the angle QPR, which has a measure of 32º+24º=56º.

Then, by a similar reasoning, we can use again the tangent function to find QR:

\begin{gathered} \tan\mleft(56º\mright)=\frac{QR}{PQ} \\ \Rightarrow QR=PQ\cdot\tan\mleft(56º\mright) \\ \Rightarrow QR=14\cdot\tan\mleft(56º\mright) \end{gathered}

We have found expressions for QS and QR in terms of trigonometric relationships. Then, we can find an expression for SR:

\begin{gathered} QS+SR=QR \\ \Rightarrow SR=QR-QS \end{gathered}

Replace the expressions for QR and QS:

SR=14\tan\mleft(56º\mright)-14\tan\mleft(32º\mright)

Use a calculator to find decimal expressions for tan(56º) and tan(32º). Then, find SR:

\begin{gathered} SR=14\times1.482560969...-14\times0.6248693519... \\ \Rightarrow SR=12.00768263... \end{gathered}

Therefore, to the nearest tenth, the length of the side SR (or RS, which is the same) is 12.0.

3 0
1 year ago
Identify the graph of 9X^2+4xy+5y^2-40=0 and find theta to the nearest degree.
lubasha [3.4K]

Answer:

The answer is ellipse; 23° to the nearest degree ⇒ answer (d)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

- 9x² + 4xy + 5y² - 40 = 0

∵ A = 9 , B = 4 , 5 = 5

∴ B² - 4 AC = (4)² - 4(9)(5) = -164 < 0

∴ B² - 4AC < 0

∴ If a conic exists, it will be either a circle or an ellipse.

* To find the type of the graph lets check;

- If A and C are nonzero, have the same sign, and are not

 equal to each other, then the graph is an ellipse.

- If A and C are equal and nonzero and have the same

 sign, then the graph is a circle.

∵ A and C have same signs and are not equal

∴ The graph is an ellipse

* If we have term xy ⇒ B ≠ 0

∴ The graph is rotate by angle Ф

* To find the angle of rotation use the rule:

- cot(2Ф) = (A - C)/B

∵ A = 9 , B = 4 , C = 5

∴ cot(2Ф) = (9 - 5)/4 = 4/4 = 1

∴ tan(2Ф) = 1

∴ 2Ф = 45°

∴ Ф = 22.5° ≅ 23° to the nearest degree

* The answer is ellipse; with angle of rotation = 23°

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4 years ago
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nikitadnepr [17]
The solve for n would be 11
2 to the second power is 4 and 4x11=44
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3 years ago
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