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3 years ago

When a object is at rest, what is it’s speed??

Physics

2 answers:

Firdavs [7]3 years ago

7 0

Answer:

the speed when object at rest is 0 m/s

nadya68 [22]3 years ago

3 0

Answer:

0 (there is no speed)

Explanation:

If an object is at rest, it is not moving, and it doesn't have a speed, so the speed is zero.

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Which gas law states that the pressure of a gas decreases when volume is increased and the temperature is unchanged?

rewona [7]

The answer is C Boyle's Law I believe

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3 years ago

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How fast does a 2 MeV fission neutron travel through a reactor core?

Artemon [7]

Answer:

The answer is $1.956 \times 10^7\ m/s$

Explanation:

The amount of energy is not enough to apply the relativistic formula of energy $E = mc^2$ , so the definition of energy in this case is

$E = \frac{1}{2}m v^2$ .

From the last equation,

$v= \sqrt{2E/m}$

where

$E = 2 MeV = 3.204 \times 10^{-13} J$

and the mass of the neutron is

$m = 1.675\times 10^{-27}\ Kg$ .

Then

$v = 1.956 \times 10^7\ m/s$

the equivalent of $0.065$ the speed of light.

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3 years ago

Why do astronomers use spectroscopes to analyze light from distant objects?

RoseWind [281]

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3 years ago

A convex lens of focal length 35 cm produces a magnified image 2.5 times the size of the object. What is the object distance if

Zanzabum

Answer:

Image distance is -52.5 cm

Image is virtual and forms on the same side of the lens and upright image is formed.

Explanation:

u = Object distance

v = Image distance

f = Focal length = 35

m = Magnification = 2.5

$m=-\frac{v}{u}\\\Rightarrow 2.5=-\frac{v}{u}\\\Rightarrow v=-2.5 u$

Lens equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{35}=\frac{1}{u}+\frac{1}{-2.5u}\\\Rightarrow \frac{1}{35}=\frac{3}{5u}\\\Rightarrow u=21\ cm$