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shutvik [7]
3 years ago
7

A 0.12-kg softball is moving at 6 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 14 m/s. what

is the change in the magnitude of the momentum of the softball?
Physics
1 answer:
Alexeev081 [22]3 years ago
5 0
Initial momentum of the ball ( say p ) = 0.12×6 =
0.72 kg-m/s

Final momentum of the ball ( say P) = 0.12×14 =
1.68 kg-m/s

Change in magnitude =
P-p = 1.68-0.72
= 0.96 Kg-m/s
____________
hope it helps !
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(x-acceleration,y-acceleration) = (-17/27,-12/27) = (-0.629629629..., -0.444...)

angle of acceleration = tan^-1 (-0.444.../-0.629629...) = 35.21759 degrees below negative x-axis.

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A push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle θ below the horizontal,
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its on wheels and they are supposed to make it eas

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2 years ago
A parallel-plate capacitor has 2.10 cm × 2.10 cm electrodes with surface charge densities ±1.00×10-6 C/m2. A proton traveling pa
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Answer:

x=0.53x10^{-3} m

Explanation:

Using Gauss law the field is uniform so

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ε=8.85x10^{-12} \frac{C^{2}}{n*m^{2}}

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Force of charge is

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F_{q}=m*a\\a=\frac{F_{q}}{m}=\frac{1.807x10^{-13}N}{1.67x10^{-27}}\\ a=1.082x0^{14} \frac{m}{s^{2}} \\t=\frac{x}{v}\\ x=2.1cm\frac{1m}{100cm}=0.021m \\v=6.7x10^{6}\frac{m}{s} \\ t=\frac{0.021m}{6.7x10^{6}\frac{m}{s}} \\t=3.13x10^{-9}s

So finally knowing the acceleration and the time the distance can be find using equation of uniform motion

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3 years ago
Compounds formed from the attraction of oppositely charged ions are called
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Answer:

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