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shutvik [7]
3 years ago
7

A 0.12-kg softball is moving at 6 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 14 m/s. what

is the change in the magnitude of the momentum of the softball?
Physics
1 answer:
Alexeev081 [22]3 years ago
5 0
Initial momentum of the ball ( say p ) = 0.12×6 =
0.72 kg-m/s

Final momentum of the ball ( say P) = 0.12×14 =
1.68 kg-m/s

Change in magnitude =
P-p = 1.68-0.72
= 0.96 Kg-m/s
____________
hope it helps !
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A hot air balloon is on the ground, 200 feet from an observer. The pilot decides to ascend at 100 ft/min. How fast is the angle
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0.0031792338 rad/s

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Using trigonometry

tan\theta=y\dfrac{y}{200}\\\Rightarrow y=200tan\theta

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\dfrac{dy}{dt}=\dfrac{d}{dt}200tan\theta\\\Rightarrow \dfrac{dy}{dt}=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow 100=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{100}{200sec^2\theta}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{1}{2}cos^2\theta

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