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Sonbull [250]
4 years ago
13

Will someone help me please :(

Physics
1 answer:
-Dominant- [34]4 years ago
7 0
The answer's 25,000 joules 
half m v squared
half 2000, x 5 squared
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A 30 kg box sits on the floor it requires 275N of force to get it moving once it is moving it only takes 225N of force.what are
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1) The coefficient of static friction is 0.935

2) The coefficient of kinetic friction is 0.765

Explanation:

1)

When a force is applied on a box sitting on the floor, the force that must be applied in order to make the box moving is equal to the maximum force of static friction between the floor and the box, which is:

F = \mu_s mg

where

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Therefore, the coefficient of static friction is

\mu_s = \frac{F}{mg}=\frac{275}{(30)(9.8)}=0.935

2)

Once the box is in motion, the force that must be applied in order to make the box moving at constant velocity is equal to the force of kinetic friction between the floor and the box, which is:

F = \mu_k mg

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\mu_k is the coefficient of kinetic friction

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m = 30 kg

g=9.8 m/s^2

F = 225 N

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\mu_k = \frac{F}{mg}=\frac{225}{(30)(9.8)}=0.765

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