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77julia77 [94]
4 years ago
12

As the total resistance is reduced in a simple electrical circuit, the current flow will _____.

Physics
1 answer:
makvit [3.9K]4 years ago
3 0
The current flow will increase 
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sun alfalfa rabbit coyote

Explanation:

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3 years ago
A point charge of 4 µC is located at the center of a sphere with a radius of 25 cm. Find the electric flux through the surface o
givi [52]

Answer:

Ф = 4.5176x10⁵ N . m² / C

Explanation:

In this case, we need to use two expressions in order to calculate the electric flux of the sphere.

First the Electric flux is calculated using this expression:

Ф = E * A  (1)

Where:

E: Electric field

A: Area of the sphere

To get the electric field E, we use this expression:

E = K * q / r²    (2)

If we replace (2) into (1) we have the following:

Ф = K * q * A / r²    (3)

Finally, we need to know the expression to get the area of a sphere which is the following:

A = 4πr²   (4)

Replacing into (3):}

Ф = K * Q * 4πr² / r²       discarting r²:

Ф = K * Q * 4π   (5)

Now, all we need to do is replace the given values and solve for the electric flux of the sphere:

Ф = 8.98755x10⁹ * 4x10⁻⁶ * 4 * π

<h2>Ф = 4.5176x10⁵ N . m² / C</h2>

Hope this helps

5 0
3 years ago
11. When an object is speeding up in the positive direction, what vs happering to its
Alina [70]

Answer:

im pretty sure its b

Note that when the acceleration is negative — on the interval [0, 2) — that means that the velocity is decreasing. When the acceleration is positive — on the interval (2, 4] — the velocity is increasing. Speeding up and slowing down.

4 0
3 years ago
Từ độ cao h=2m một vật bắn lên với vận tốc ban đầu V0=10(m/s), hợp với phương ngang 1 góc 30 độ.Hãy xác minh
nydimaria [60]

Answer:

A IS THE ANSWER

Explanation:

HOPE IT HELPS AND PLEASE MARK AS BRAINLIST

8 0
3 years ago
A cat dozes on a stationary merry-go-round, at a radius of 5.7 m from the center of the ride. Then the operator turns on the rid
tatyana61 [14]

Answer:

0.76

Explanation:

we are given:

radius (r) =5.7 m

speed (s) = 1 revolution in 5.5 seconds

acceleration due to gravity (g) = 9.8 m/s^{2}

coefficient of friction (Uk) = ?

 we can get the minimum coefficient of friction from the equation below

centrifugal force = frictional force

m x r x ω^{2} = Uk x m x g

r x ω^{2} = Uk x g

Uk = \frac{ r x ω^{2} }{g}

where ω (angular velocity) = \frac{2π}{time}

= \frac{2π }{5.5} = 1.14

Uk = \frac{ 5.7 x 1.14^{2} }{9.8} = 0.76

6 0
4 years ago
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