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Katen [24]
3 years ago
7

In what ways would organisms living in very deep water need to be specialized?

Physics
1 answer:
Nady [450]3 years ago
8 0

Organisms living in great depths of water bodies like oceans and lakes need to be adapted for two (2) things especially; high water pressure and vision in darkness

The water column above from deep in the water can cause lots of hydrostatic pressure on the organisms’ cells. Also the fact that light cannot penetrate to great depth of water due to diffusion means the organisms must live in darkness.

Explanation:

It has been shown that cells from Piezophile bacteria have a high percentage of fatty acids in their membranes to prevent the cells from compacting solid from the high pressure.

Most of the organisms are also detritivores and use chemosynthesis for the autotrophs because light cannot reach these depths and hence photosynthesis is not possible.  Organisms with eye vision are adapted to high wavelength light that can at least reach greater depths before diffusing. Nonetheless natural selection would favour use of sight for most organisms in this benthic region.

Learn More:

For more on adaptation check out;

brainly.com/question/12959056

brainly.com/question/350553

#LearnWithBrainly

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Only about 50% of the solar energy directed toward Earth penetrates directly to the surface. Explain what happens to the rest of
Tresset [83]

Answer:

it is absorbed or reflected by the atmosphere

Explanation:

In the case when approx 50% only of the solar energy would be directed towards earth and it would be penetrates directly to the surface so the rest or remaining of the radiation would be either absorbed or refected by the atmosphere

So as per the given situation the above represent the answer

hence, the same is to be considered and relevant

4 0
3 years ago
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Two 1.9 kg masses are 1.1 m apart (center to center) on a frictionless table. Each has + 9.6 μC of charge.
Anni [7]

Answer:

F= 0.6 N

Explanation:

Fe(electrical force)=k q1q2/r^2

    k=9*10^9\\q1=-9.6 *10^-6 C\\q2= -9.6*10^-6 C\\r= 1.1m

So,    

        F=\frac{9*10^9*-9.6 *10^-6 C* -9.6*10^-6 C}{1.1^2}

         F= 0.6 N

5 0
3 years ago
In a single-slit diffraction experiment, a coherent light source illuminates a slit in a barrier, and the resulting pattern is p
UkoKoshka [18]

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Explanation:

4 0
2 years ago
I really need help on this question!​
steposvetlana [31]

Answer:

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4 0
3 years ago
a 1-kg discus is thrown with a velocity of 19 m/s at an angle of 35 degrees from the vertical direction. calculate the vertical
nlexa [21]

Answer:

Vx =  10.9 m/s ,  Vy = 15.6 m/s

Explanation:

Given velocity V= 19 m/s

the angle 35 ° is taken from Y-axis so the angle with x-axis will be 90°-35° = 55°

θ = 55°

to Find Vx = ? and Vy= ?

Vx = V cos θ

Vx = 19 m/s  × cos 55°

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Vx = V sin θ

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Vy = 15.6 m/s

6 0
3 years ago
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