Answer:
1.) x+2
2.) x+4
Step-by-step explanation:
I got it right on Edge, hope this helps
In an examination, 70% of the candidates passed in English, 80% passed in mathematics, and 10% failed in both subjects. If 144 candidates passed in both, what is the total number of students?
Let the total no of students be 100x
No of students failed =10*100x /100 = 10x
Thus , no of students passed = 100x - 10x = 90x
No of students passed in english = 7* 100x /100 =70x
No of students passed in maths = 8*100x / 100 =80x
Therefore no of students who passed in both = (80x + 70x) - 90x = 60 x
{{ Draw a venn diagram to understand this point ,
Or you could think like this:- when we add no of students passing in m and e individually ,we are counting those students who passed in both twice ,
Thus total students passed will be sum of no of students passed in maths and english individually - those who passed both.
Rearrange this eqn to get the one used above}}
Thus 60x = 144
Or, 100x = (144 * 100)/60=240
Therefore total no of students = 240
Hope you understood
Forgive me if I’m wrong
Can you mark as brainlist really need it.
We can see by manually counting the squares, that
BC has a length of 2 and AC has a length of 3
using the pythagorean theorem, which is a²+b²=c², we can figure out the length of the missing side, AB.
a, is one side of the triangle
b, is another side
c, is always the hypotenuse, or the slanted side.
so if we fill this in with the appropriate numbers, we can solve for c
(2)² + (3)² = c²
4 + 9 = c²
13 = c²
square root both sides
√13 = √c²
√13 = c
√13 ≈ 3.6056 units
Answer:
Step-by-step explanation:
that is the answer
Answer:
there were 200 children and 500 adults at the show
Step-by-step explanation:
7x+10y=6400
x+y=700
x=700-y
7(700-y)+10y=6400
4900-7y+10y=6400
-7y+10y=1500
3y=1500
y=500
x=700-y
x=700-500
x=200