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2 years ago

Two sides of a rectangle differ by 35 cm. Find the dimensions of rectangle of its perimeter is 67 cm

Mathematics

1 answer:

Effectus [21]2 years ago

7 0

Answer:

one side is 137/4 and other is 3/4

Step-by-step explanation:

all steps are in picture

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Determine the lengths of the sides of the rectangle using the given area. Give answers both exactly and

Degger [83]

Answer:

Part a) Exactly values

The width of the rectangle is $\frac{\sqrt{70}}{2}\ cm$

The length of the rectangle is $2\sqrt{70}\ cm$

Part b) Approximately values

The width of the rectangle is $4.2\ cm$

The length of the rectangle is $16.7\ cm$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of rectangle is equal to

$A=LW$

we have

$L=4x\ cm\\W=x\ cm$

substitute the values in the formula

$A=4x(x)$

$A=4x^2$

$A=70\ cm^2$

$70=4x^2$

Solve for x

Divide by 4 both sides

$\frac{70}{4}=x^2$

square root both sides

$x=(+/-)\frac{\sqrt{70}}{2}$

The solution is the positive value

$x=\frac{\sqrt{70}}{2}$

therefore

<em>Exactly values</em>

$L=4\sqrt{70}}{2}=2\sqrt{70}\ cm\\\\W=\frac{\sqrt{70}}{2}\ cm$

<em>Approximately values</em>

$L=4\sqrt{70}}{2}=16.7\ cm\\\\W=\frac{\sqrt{70}}{2}=4.2\ cm$

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Step-by-step explanation:

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Hepl with polynomials (2/3Y2 - 3/4) + (5/6Y2 + 4)

hodyreva [135]

4y/3 - 3/4 + 5/6y (multiply by) x 2 + 4

4y/3 - 3/4 + 5y/3 + 4

collect like terms: (4y/3 + 5y/3) + ( - 3/4 + 4)

simplify: 3y + 13/4 <----- FINAL ANSWER

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3 years ago

Two sides of a rectangle differ by 35 cm. Find the dimensions of rectangle of its perimeter is 67 cm​

Two sides of a rectangle differ by 35 cm. Find the dimensions of rectangle of its perimeter is 67 cm