When working with scientific data, the average of a data set is called the

A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m

nata0808 [166]

A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m h c l was dispensed. Based on this titration, what is the k s p of a g o h <u>. Ksp=1.9×10⁻⁸</u>

<h3>What is titration?</h3>

Titration is a typical laboratory technique for quantitative chemical analysis used to calculate the concentration of a specified analyte. It is also referred to as titrimetry and volumetric analysis (a substance to be analyzed). A standard solution with a known concentration and volume is prepared as the reagent, also known as the titrant or titrator. To ascertain the concentration of the analyte, the titrant reacts with an analyte solution (also known as the titrand). The titration volume is the amount of titrant that interacted with the analyte.

A typical titration starts with a beaker or Erlenmeyer flask being placed below a calibrated burette or chemical pipetting syringe that contains the titrant and a little amount of the indicator (such as phenolphthalein).

To learn more about titration from the given link:

brainly.com/question/186765

#SPJ4

5 0

2 years ago

How many moles would contain 1.50 x 1024 atoms of sodium?

riadik2000 [5.3K]

<h3>Answer:</h3>

2.5 moles

<h3>Explanation:</h3>

<u>We are given;</u>

1.5 × 10^24 atoms

We are required to determine the number of moles of sodium.

We know that, 1 mole of an element contains a number of atoms equivalent to the Avogadro's number, 6.022 × 10^23.
That is, 1 mole of an element = 6.022 × 10^23 atoms.

Therefore;

1 mole of sodium contains 6.022 × 10^23 atoms

To get the number of moles;

= Number of atoms ÷ Avogadro's number

= 1.5 × 10^24 atoms ÷ 6.022 × 10^23 atoms/mol

= 2.49 moles

= 2.5 moles

Therefore, 2.5 moles of sodium contains 1.50 × 10^24 sodium atoms

5 0

3 years ago

As with any combustion reaction, the products of combusting a hydrocarbon fuel (CxHy) with oxygen (O2) are carbon dioxide (CO2)

melisa1 [442]

<u>Answer:</u>

<em>5 molecules of oxygen will be present </em>

<u>Explanation:</u>

<em>In this reaction combustion is taking place hence there must be presence of oxygen in it. </em>

We don't know the initial amount of carbon molecules in hydrogen molecules present hence the equation goes:-

$CxHy + O_2 => CO_2+ H_2O$

Mass of fuel 16.74 grams, Mass of carbon dioxide is 1198 gram and water is 0.0654 remaining mass of fuel is 16.70 g. Hence amount of fuel used up is 0.04 gram

<em> $0.04 + O => 0.1198 + 0.0654$ </em>