Answer:
The chemical equation that is properly balanced is;
e. Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O
Explanation:
To solve the question, we note the reactions thus and we look for a reason why the reaction is not balanced as follows.
a. CH₃CHO + 3O₂ → 2CO₂ + 2H₂O
Here we have 7 oxygen atoms in the reactant and 6 in the products
Not balanced
b. NH₄NO₃ → 2H₂O + N₂
Here we have three oxygen in the reactant and four in the products = Not balanced
c. Na₂CO₃ + 2H₂SO₄ → Na₂SO₄ + 2H₂O + CO₂
Here we have 11 oxygen atoms in the reactant and 8 in the products = Not balanced
d. 2Na₂SO₄ + 3Bi(NO₃)₃ → Bi₂(SO 4)₃ + 9NaNO₃
Here we have 2 Na in the reactants and 9 Na in the products = Not balanced
e. Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O
Here we have equal number of products and reactants = Balanced chemcal reaction equation.
Reaction is NH4OH <-> NH4+ OH- (note this is reversible)
Draw up an ICE table
Let x be equilibrium conc of OH- assume init conc of OH is 0M and init conc of NH4+ is 0M also. Init conc of NH4OH is 0.1M so equilibrium conc will be 0.1-x.
%dissociation = x/0.1-x * 100%
1 = 100x/0.1-x
0.1-x = 100x
101x = 0.1
x = 0.0009901
pOH = -log(0.0009901) = 3.00
