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2 years ago

Walking along a 6-meter beam without falling helps to develop __________.

Physics

2 answers:

Gala2k [10]2 years ago

7 0

Walking along a 6-meter beam without falling helps to develop C. BALANCE.

IrinaVladis [17]2 years ago

4 0

C is correct answer.

Walking along a 6 meter beam without falling helps to develop balance.

Hope it helped.

-Charlie

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A transformer connected to a 120-V (rms) ac line is to supply 12,500 V (rms) for a neon sign. To reduce shock hazard, a fuse is

Tamiku [17]

Answer:

a) 104

b) 106

c) 884 mA

Explanation:

The ratio of the transformer is given by:

$N=\frac{V_{out}}{V_{in}}=\frac{12500V}{120V}=104$

We need to know the current in the primary in order to obtain the power applied.

$I_1=I_2*N=8.50mA*104=884mA\\\\P=I*V=884*10^{-3}A*120V=106W\\$

The current rating of the fuse is the current on the primary, 884mA as we calculated before in order to obtain the power.

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3 years ago

An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 61.0 cm mark on the track. The glider compl

Novosadov [1.4K]

Answer:

T = 2.82 seconds.

The frequency $\mathbf{f = 0.36 \ Hz}$

Amplitude A = 25.5 cm

The maximum speed of the glider is $\mathbf{v = 56.87 \ rad/s}$

Explanation:

Given that:

the time taken for 11 oscillations is 31 seconds ;

SO, the time taken for one oscillation is :

$T = \frac{31}{11}$

T = 2.82 seconds.

The formula for calculating frequency can be expressed as :

$f = \frac{1}{T}$

$f = \frac{1}{2.82}$

$\mathbf{f = 0.36 \ Hz}$

The amplitude is determined by using the formula:

$A = \frac{d}{2}$

The limits that the spring makes the oscillations are from 10 cm to 61 cm.

The distance of the glider is, d = (61 - 10 )cm = 51 cm

Replacing 51 for d in the above equation

$A = \frac{51}{2}$

A = 25.5 cm

The maximum speed of the glider is:

$v = A \omega$

where ;

$\omega = \frac{2 \pi}{T}$

$\omega = \frac{2 \pi}{2.82}$

$\omega = 2.23 \ rad/s$

$v = A \omega$

$v = 25.5 *2.23$

$\mathbf{v = 56.87 \ rad/s}$

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3 years ago

A water balloon is dropped out of a fifth floor window and hits an unsuspecting person below 4.0 seconds later. The window is ap

andrew11 [14]

Answer:

80 meters high

Explanation:

The velocity of the balloon would be g*t (I won't calculate, but will us this later)

We know that the kinetic energy at the bottom equals the potential at the top.

KE = PE

1/2 * m * v^2 = m * g * h

1/2 * m * (g * t)^2 = m * g * h (substitution)

1/2 * m * g^2 * t^2 = m * g * h

1/2 * g * t^2 = h (simplification by dividing the commons between both sides)

h = 1/2 * 9.81 * 4^2

h = 78.48 m (roughly 80 m)

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3 years ago

According to Newton's third law, two objects interacting under a force (such as gravity) both feel the same force. If the planet

asambeis [7]

Explanation:

That's because the Sun's acceleration is much smaller

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2 years ago

Alex is standing still and throws a football with a speed of 10 m/s to his friend, who is also standing still. The two friends a

Phantasy [73]

The question is incomplete. It comes with a set of answer choices.

These are the answer choices:

Alex observes it as 10 m/s, and his friend observes it as less than 10 m/s.

Alex observes it as less than 10 m/s, and his friend observes it as 10 m/s.

Both Alex and his friend observe it as 10 m/s.

Both Alex and his friend observe it as less than 10 m/s.

Answer: Both Alex and his friend observe it as 10 m/s.

Justification:

1) The speed is relative to the frame of reference.

2) It is said that the both Alex and his friend are standing still.

3) Then, the speed they both see is the same, 10 m/s, respect the Earth (where they are standing still).

Of course, Alex is watching the ball moving away and his friend is seing it approaching, but it is not relevant for the question, as it deals with the speed which is only about magnitude, not direction.

7 0

2 years ago

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