We have:
s=3,7km (3700m)
u=0
v=26m/s
a=
t=
We look up for a formula to solve for a:
v²=u²+2as u²=0 so
v²=2as
(26m/s)²=2a3700m
676/7400=a
a=0,09m/s²
Answer:
Yes it is possible to increase the power with out changing the amount of work.
Explanation:
The power is defined by the amount of power divided by the time. This time is the one needed to do the work. We can understand this issue by analyzing an example with numeric values.
Work = 500 [J]
Time = 5 [s]
Power will be:
![Power=\frac{500}{5} \\Power=100 []watt]\\](https://tex.z-dn.net/?f=Power%3D%5Cfrac%7B500%7D%7B5%7D%20%5C%5CPower%3D100%20%5B%5Dwatt%5D%5C%5C)
Now if we change the time to 2 seconds:
![Power = 500 [J]/2[s]\\Power = 250 [watt]\\](https://tex.z-dn.net/?f=Power%20%3D%20500%20%5BJ%5D%2F2%5Bs%5D%5C%5CPower%20%3D%20250%20%5Bwatt%5D%5C%5C)
As we can see, the power was increased without the need to change the work.
<span>The volume of a cube is given by s^3. So the volume of this block is 3cm x 3cm x3 cm = 27 cm^3. density = mass/volume =27 g / 27 cm^3 = 1 g/cm^3.</span>
The strongest of the natural forces is Strong Nuclear, followed by Electromagnetic, then Weak Nuclear and lastly Gravitational.
So from weakest to strongest: gravitational --> weak nuclear --> electromagnetic --> strong nuclear
Answer C)
Answer: B
Explanation:
The reason why because the jet are far away at first then when the jet come near it louder