Hello!
A portable DVD player requires six 1.5-volt batteries to operate. If the resistance in the circuit is 7.2 ohms, what is the current?
Data:
We have six 1.5 volt batteries, soon, your tension (V)
V = 1.5 * 6 = 9 Volts
R (resistance) = 7.2 ohms
I (Current intensity) = ? (in Amps)
Solving (Ohm's First Law):
Answer:
The current is 1.25 amps
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Answer:
0 km/h vertically, horizontally yet 350 km/h
Explanation:
The bundle was inside the plane, so it start a free fall movement from rest, i.e., 0km/h, but of course the speed increases with gravity, at 9,8m/s^2 over time, but since here it is asked the vertical speed at the beginning, it is 0 km/h.
1 Kilojoule [kJ] = 737.562 149 277 27 Foot pound force [ftlbf]
OPTION (C) IS CORRECT
ANSWER - UNIFORM MOTION
If there is no change in the velocity of the object then it is known to be in <u>UNIFORM MOTION</u>.
EXPLORE MORE:-
EXAMPLE - A CAR COVERS A DISTANCE OF 15 KM WE'D EVERY 2 HOURS
FOR AN UNIFORM MOTION, ACCELERATION IS ZERO , AS THERE IS NO CHANGE IN VELOCITY....
-THANKS.!!
Answer: a. E =9.9*EXP(-19)J
1 mole E= 596178J
b. E= 1.32*EXP(-15)J, 1 mole E=795MegaJ
c. E= 1.98*EXP(-23)J
1 mole E = 11.9J
Explanation: The Energy of a photon E, the wavelength are related by
E= h*c/wavelength
h is the Planck's constant 6.6*EXP(-34)J.s
c is speed of light 3*EXP(8)m/s
h*c=1.98*EXP(-25)
Now let's solve
a. E = h*c/wavelength
= h*c/(200*EXP(-9)m
=9.9*EXP(-19)J
1 mole of a photon contian 6.022*EXP(23)photons by advogadro
Now to get the energy of 1 mole of the photon we have
9.9*EXP(-19)*6.023*EXP(23)
=596178J
b. E=h*c/150*EXP(-12)m
=1.32*EXP(-15)J
1 mole will have
1.32*EXP(-15)*6.022*EXP(23)J
=795*EXP(6)J
c. E= h*c/1*EXP(-2)m
=1.98*EXP(-23)J
1 mole of the photon will have
1.98*EXP(-23)J *6.022*EXP(23)
= 11.9J.
You will notice that the longer the wavelength of the photon the lesser the Energy it as.
NOTE: EXP represent 10^
