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Diano4ka-milaya [45]
4 years ago
12

Convert 0.592 hm to cm. *

Physics
1 answer:
sattari [20]4 years ago
3 0

<em>Answer:</em>

<em>5920 cm</em>

<em>Explanation:</em>

<em>1 hm = 100m</em>

<em>1 m = 100cm</em>

<em>1 hm = 100×100cm = 10000 cm</em>

<em>0.592 hm = 0.592×10000cm = 5920 cm</em>

<em>Good luck !</em>

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4 years ago
A plastic block of mass 0.20.2kg is initially at rest on a horizontal frictionless surface. A bullet of mass 1212 g is fired wit
Juli2301 [7.4K]

Answer:

94.29619%

Explanation:

m_1 = Mass of bullet= 0.012 kg

m_2 = Mass of block = 0.2 kg

u_1 = Initial Velocity of bullet= 550 m/s

u_2 = Initial Velocity of block = 0 m/s

v_1 = Final Velocity of bullet = 20 m/s

v_2 = Final Velocity of block

As the linear momentum of the system is conserved

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{0.012\times 550+0.2\times 0-0.012\times 20}{0.2}\\\Rightarrow v_2=31.8\ m/s

Change in kinetic energy is given by

\Delta K=\dfrac{1}{2}(m_1u_1^2-m_1v_1^2-m_2v_2^2)\\\Rightarrow \Delta K=\dfrac{1}{2}(0.012\times 550^2-0.012\times 20^2-0.2\times 31.8^2)\\\Rightarrow \Delta K=1711.476\ J

Percentage change is given by

\dfrac{\Delta K}{\dfrac{1}{2}m_1u_1^2}\times 100=\dfrac{1711.476}{\dfrac{1}{2}0.012\times 550^2}\times 100=94.29619\ \%

The percent of the initial kinetic energy of the bullet block system is lost during the collision is 94.29619%

4 0
3 years ago
1. How fast must a truck travel to stay beneath an airplane that is moving
Xelga [282]

Answer:

The truck must travel by 95.16 km/h to stay beneath the airplane

Explanation:

Lets explain how to solve the problem

How fast must a truck travel to stay beneath an airplane that is moving

105 km/h at an angle of 25° to the ground

The truck moves a long the horizontal ground

The airplane moves 105 km/h at an angle 25° to the ground

The truck must moves with velocity equal the horizontal component

of the velocity of the airplane to stay beneath the airplane

The angle between the line represented the velocity of the airplane

and the ground is 25°

→ The horizontal component of the velocity = v cos(25)

→ The velocity of the airplane is 105 km/h

→ The horizontal component = 105 cos(25) = 95.16 km/h

The velocity of the truck = the horizontal component of the airplane

<em>The truck must travel by 95.16 km/h to stay beneath the airplane</em>

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A hypothesis can also be called
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