All categories

3 years ago

During sexual reproduction, each parent contributes

Physics

1 answer:

Snowcat [4.5K]3 years ago

4 0

Answer:

I don't understand what exactly you're asking, but this statement is true.

Explanation:

You might be interested in

The client centered approach is emphasized by

nikklg [1K]

Answer:

The client-centered approach emphasized the role of the therapist as a facilitator of growth and honored the inherent power of the client.

NOT Emphasis is given to developing a contract for therapy.

6 0

3 years ago

II. IDENTIFY THE TYPE OF FORCE

uysha [10]

Answer:

Explanation:

1. Frictional force is responsible for running of car and buses on roads.

2.Gravitational force exists between astronauts in space.

3. Magnetic for is responsible to attract the iron objects using a magnet

4.Electrostatic force is responsible for fiber to stick on the skin.This force occurs due to the presence of charge.

5.When a person is pushing a trolley then object experience a normal reaction from ground.

6.Gravitational force makes the planet to move in their orbits.

4 0

3 years ago

In the diagram, q1 = -6.39*10^-9 C and q2 = +3.22*10^-9 C. What is the electric field at point P? pls help

Alexxx [7]

Answer:

Below

Explanation:

First draw the vectors that represent both electric fields.

E1 is the elictric field created by q1, E2 is the one created by q2.

● q1 is negative so E1 will point from P.

● q2 is positive so E2 will point out of P

(Picture below)

■■■■■■■■■■■■■■■■■■■■■■■■■■

The resulting electric field is equal to the sum of the two fields since both vectors are colinear.

Let E be the total field.

● E = E1 + E2

The formula of the electric field intensity is:

● E = K ×(q/d^2)

-K is Coulomb's constant

-d is the distance between the charge and the object ( here P)

-q is the charge

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E1 = K × (q1/d1^2)

The distance between q1 and P is the qum of 0.15 m 0.25 m. (0.4 m)

Coulombs constant is 9×10^9 m^2/C^2

● E1 = 9×10^9 ×[-6.39 × 10^(-9)/ 0.4^2]

● E1 = -359.43 N/C

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E2 = K ×(q2/d^2)

The distance between q2 and P is 0.25 m.

● E2 = 9×10^9×[3.22×10^(-9) /0.25^2]

● E2 = 463.68 N/C

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E = E1 + E2

● E = -359.43+463.68

● E = 105.25 N/C

4 0

3 years ago

Read 2 more answers

A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.1 cm/min. At what rate is the volume of

andrew11 [14]

Answer:

$\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Explanation:

Knowing that the volume of a sphere is V=(4/3)πr³ and $\frac{dr}{dt}=-0.1\frac{cm}{min}$

We must find $\frac{dV}{dt}=?$ when r=14cm

V=(4/3)πr³ ⇒

$\frac{dV}{dt}=\frac{4}{3}\pi3r^{2}\frac{dr}{dt}\\\frac{dV}{dt}=4\pi r^{2}(-0.1\frac{cm}{min})$

and r=14cm then

$\frac{dV}{dt}=4\pi(14cm)^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=4\pi196cm^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Note: as you can see the relationship of change of r with respect to t is negative because it is a decrease, and also its volume ratio

4 0

4 years ago

As the period of a wave increases, the frequency increases.

Anarel [89]

See the picture below

3 0

3 years ago

Read 2 more answers