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lukranit [14]
3 years ago
15

Easy question please answer I need help

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

The equation representing the Total amount spend on movies for a year is C(m) = 6m+25.

We can say that Domain can be represented as Whole Number or an Integer or A Real Number so any value can be selected.

Step-by-step explanation:

Given:

Annual Registration fee of the club = $25

Discounted price of each ticked for members = $6

Number of tickets Makayla Purchases in a year = 'm'

We need to model the equation the amount of Money Makayla spent on movies for the year while becoming a member.

Now we know that:

Total Amount of Money spend on Movie tickets C(m) is equal to Sum of Discounted price of each ticked for members multiplied by Number of tickets Purchases in a year and Annual Registration fee of the club.

Framing in equation for we get;

C(m) = 6m+25

Hence The equation representing the Total amount spend on movies for a year is C(m) = 6m+25.

Also We can say that Domain can be represented as Whole Number or an Integer or A Real Number so any value can be selected.

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A deck contains these cards of the same size and shape.
alex41 [277]

Step-by-step explanation:

Total cards that deck contains= 5+4+2+1=12 ( as mentioned in question)

So,

1. Probability of getting blue card is 1/12

2. Probability of getting a red card is 2/12=1/6

hope it helps

3 0
3 years ago
What is the value of x when x + 7 = 21? <br> A) -28 <br> B) -14 <br> C) 3 <br> D) 14
DerKrebs [107]
The answer would be D
4 0
3 years ago
Read 2 more answers
Is 63 greater than 48.1 or less than<br><br>PLEASE HELP QUICKLY AS POSSIBLE THANK YOU :)​
timofeeve [1]

Answer:

63 is greater than 48.1 ...

63 > 48.1

Step-by-step explanation:

63 is greater than 48 remember. So you need to remove the [.1] and focus on the 63 and 48.

<h3>Hope it helps!!</h3><h3><em>Please</em><em> </em><em>mark me as the brainliest</em><em>!</em><em>!</em><em>!</em></h3>

<em>Thanks</em><em>!</em><em>!</em><em>!</em><em>!</em><em>❤</em><em>❣</em><em>❤</em>

<h2><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>:)</h2>
5 0
3 years ago
Read 2 more answers
Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The
ExtremeBDS [4]

Answer:

  • 800 kph
  • 600 kph

Step-by-step explanation:

<u>Equation</u>

Let s represent the speed of the faster plane. Then its travel time is ...

  time = distance/speed = 3600/s

travel time for the slower plane is ...

  time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

  3600/(s -200) -3600/s = 1.5

<u>Solution</u>

Multiplying by (2/3)s(s -200), we get ...

  2400(s) -2400(s -200) = s(s -200)

  s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

  (s -800)(s +600) = 0 . . . . . . . . . . . . . factor

The positive value of s that makes a factor zero is s = 800.

<u>Conclusion</u>

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

<em>Check</em>

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

6 0
3 years ago
The number of text messages sent daily by a student is a poisson random variable with parameter λ=5 .in a class with 20 independ
Rudik [331]
This problem is a combination of the Poisson distribution and binomial distribution.

First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961

For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5)   or approximately
=0.00006181
7 0
3 years ago
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