Answer:
D
Step-by-step explanation:
For simplify the work we can start to factorise all the possibles expressions:
2x + 8.
8 is multiple of 2, so it can became
2(x+4)
x^2 - 16 this is a difference of two squares, so it can be rewritten as:
(x+4)(x-4)
x^2 + 8x + 16
we have to find two numbers whose sum is 8 and whose product is 16
the two number are 4 and 4
it becames:
(x+4)(x+4)
x+ 4 can‘t be simplified
if we look at the expression, we can find that x-4 appears at the numerator so
x^2 - 16 must be at numerator
but the second factor (x+4) doesn’t appear, so has been simplified. This situation can be possible only in the D option
in fact
(x+4)(x-4)/2(x+4) * (x+4)/(x+4)(x+4)
it became
(x+4)(x-4)/2 * 1/(x+4)(x+4)
(x-4)/2(x+4)
ANSWER
![g(x) = \sqrt{x + 4}](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Csqrt%7Bx%20%2B%204%7D%20)
EXPLANATION
The parent square root function is
![f(x) = \sqrt{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20)
The translation
![g(x ) = \sqrt{x + k}](https://tex.z-dn.net/?f=g%28x%20%29%20%3D%20%20%5Csqrt%7Bx%20%2B%20k%7D%20)
Will shift the graph of f(x) k units to left.
The translation
![g(x) = \sqrt{x -k}](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Csqrt%7Bx%20-k%7D%20)
will shift the graph of f(x) to the right by k units.
Therefore if f(x) is shifted 4 units to the left its new equation is:
![g(x) = \sqrt{x + 4}](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Csqrt%7Bx%20%2B%204%7D%20)
Answer:
x =2
2 in, 6 in, 1 in
Step-by-step explanation:
2-3 12 INCH RULERS
sorry 4 caps
Answer:
|-8|
if you are happy with my answer, please give brainliest :)
Step-by-step explanation:
Absolute value of -8 is 8, which is greater than the other values.