Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
I would do the work out but it’s a lot of work so heres a picture the work is already done.
Answer:
14 knots
Step-by-step explanation:
We know the speed (55 knots) is 6 more than 3.5 times the winner of the monohull in the 2007 tournament.
So let's set the variable for the speed of the monohull to <em>m</em>. Now, let's set up an equation:

We can solve this by first subtracting 6 from both sides to get:

Dividing both sides by 3.5 we get:

That means that the top speed of the monohull in the 2007 tournament was 14 knots
Answer:
769 cubic ft
Step-by-step explanation:
Its volume:
Find the volume of a cylinder of radius 7 ft and length 5 ft:
The basic formula for his volume is V = πr²h. In this case, the volume is:
V = 3.14(7 ft)²(5 ft) = 769 cubic feet of water.