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In-s [12.5K]
3 years ago
6

The distance traveled by an object can be modeled by the equation d = ut + 0.5at2 where d = distance, u = initial velocity, t =

time, and a = acceleration. Solve this formula for a. Show all steps in your work. plz someone >~
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
6 0

Given d = ut + 0.5at2, and assuming d or distance, u or initial velocity, and t or time are known, acceleration or a could be solved.

d – ut =0.5at2

(d – ut)/(t^2) = 0.5a

( d – ut)/[(0.5)(t^2)] = a

Hope this helps

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Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have
boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0
3 years ago
Solve the system of linear equations by substitution.<br><br> −5x+3y=51<br> y=10x−8
DerKrebs [107]
I would do the work out but it’s a lot of work so heres a picture the work is already done.

3 0
2 years ago
On a cloudy day, Yong Sun needed to know the height of a window in a building. Yong Sun positioned a mirror on the ground betwee
const2013 [10]
Its a ratio problem

height/34.15 = 1.89/.2288
4 0
4 years ago
A trimaran boat, with a top speed of 55 knots, won the tournament cup in 2010. Its top speed is 6 knots more than 3.5 times the
slavikrds [6]

Answer:

14 knots

Step-by-step explanation:

We know the speed (55 knots) is 6 more than 3.5 times the winner of the monohull in the 2007 tournament.

So let's set the variable for the speed of the monohull to <em>m</em>. Now, let's set up an equation:

55 = 6 + (3.5 * m)

We can solve this by first subtracting 6 from both sides to get:

49 = 3.5 * m

Dividing both sides by 3.5 we get:

14 = m

That means that the top speed of the monohull in the 2007 tournament was 14 knots

4 0
3 years ago
You have a new pool and want to know it's volume. The pool is 5 feet deep and has a radius of 7 feet. About how much water can t
MrRa [10]

Answer:

769 cubic ft

Step-by-step explanation:

Its volume:

Find the volume of a cylinder of radius 7 ft and length 5 ft:

The basic formula for his volume is V = πr²h.  In this case, the volume is:

V = 3.14(7 ft)²(5 ft) = 769 cubic feet of water.

3 0
3 years ago
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